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Dovator [93]
3 years ago
12

A dumbell has a mass of 95 kg. What force must be applied to accelerate it upward at 2.2 m/s2?

Physics
1 answer:
Sveta_85 [38]3 years ago
5 0
A :-) F = ma
Given - m = 95 kg
a = 2.2 m/s^2
Solution -
F = ma
F = 95 x 2.2
F = 209

.:. The force is 209 N
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Its velocity would be constant 
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A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.7 1010 m (inside the orbit
Lubov Fominskaja [6]

Answer:

58515.9 m/s

Explanation:

We are given that

d_1=4.7\times 10^{10} m

v_i=9.5\times 10^4 m/s

d_2=6\times 10^{12} m

We have to find the speed (vf).

Work done by surrounding particles=W=0 Therefore, initial energy is equal to final energy.

K_i+U_i=K_f+U_f

\frac{1}{2}mv^2_i-\frac{GmM}{d_1}=\frac{1}{2}mv^2_f-\frac{GmM}{d_2}

\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2}=\frac{1}{2}v^2_f

v^2_f=2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})

v_f=\sqrt{2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})}

Using the formula

v_f=\sqrt{v^2_i+2GM(\frac{1}{d_2}-\frac{1}{d_1})}

v_f=\sqrt{(9.5\times 10^4)^2+2\times 6.7\times 10^{-11}\times 1.98\times 10^{30}(\frac{1}{6\times 10^{12}}-\frac{1}{4.7\times 10^{10})}

Where mass of sun=M=1.98\times 10^{30} kg

G=6.7\times 10^{-11}

v_f=58515.9 m/s

4 0
3 years ago
At the lowest point in a vertical dive (radius = 0.58 km), an airplane has a speed of 300 km/h which is not changing. Determine
murzikaleks [220]

Answer:

The centripetal acceleration is a = 11.97 \ m/s^2

Explanation:

From the question we are told that

     The radius  is r =  0.58 \ km =  0.58 * 1000  =  580 \ m

      The speed is v  = 300\ km /hr =  \frac{300 *1000}{1 * 3600 }  =  83.33 \ m/s

The centripetal acceleration of the pilot is mathematically represented as

       a =  \frac{v^2 }{r}

substituting  values

      a =  \frac{(83.33)^2 }{580}

     a = 11.97 \ m/s^2

7 0
3 years ago
Which best describes a relationship among the vectors? Vectors P and Py are components of vector Px. Vectors Px and Py are compo
mafiozo [28]
If we have a vector P, then we name it's components by the axis we project it onto.

In 2D Cartesian coordinate system we have one x axis and one y axis.

Vector P can then be represented with two components: Px and Py.

Px is the component of vector P on the x axis and Py is the component of the vector P on the y axis. 
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Answer:

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Explanation:

This shows fall because the Earth is a little tilted not giving as much light

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3 years ago
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