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Svetllana [295]
4 years ago
5

What is the Hsol for KBr k+ + br- ? The lattice energy is –679 kJ, the enthalpy of hydration for is –336 kJ/mol, and the enthalp

y of hydration for is –284 kJ/mol. Use Hsol = –Hlat + Hhydr. –627 kJ/mol –59 kJ/mol 59 kJ/mol 1,299 kJ/mol
Chemistry
1 answer:
iren [92.7K]4 years ago
7 0
The enthalpy change of the solution represents the change in enthalpy when one mole of a certain ionic substance would dissolve in water. It can be calculated from the sum of the lattice energy and the enthalpy of hydration. We calculate as follows:

Hsol = 679 kJ + –336 kJ/mol + <span> –284 kJ/mol = 59 kJ/mol</span>
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Explanation:

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An object that has the ability to do work has __________ energy.
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potential

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1 year ago
A water treatment plant receives the source water with an average Ca2+ concentration of 46.9 mg/L and Mg2+ concentration of 14.8
Veronika [31]

Answer:

42,650 kg of calcium carbonate will be produced everyday.

13,600.5 kg of magnesium hydroxide will be produced everyday.

Explanation:

Concentration of calcium ions = 46.9 mg/L

Concentration of magnesium ions = 14.8  mg/L

Volume of solution treated everyday , V= 80 million gal

= 80\times 10^6 gal=4.546\times 80\time 10^6 L=3.637\times 10^8 L

1 gallon = 4.546 Liter

Mass of  calcium ion in V = 46.9 mg/L\times 3.637\times 10^8 L

=  1.706\times 10^{10} mg

1 mg = 0.001 g

1.706\times 10^{7} g

Moles of calcium ions = \frac{1.706\times 10^{7} g}{40 g/mol}=426,500 mol

From 1 mole of calcium ion 1mol of carbonate is formed . then from 426,500 moles of calcium ion will form :

\frac{1}{1}\times 426,500 mol=426,500 mol of calcium carbonate

Mass of 426,500 moles of calcium carbonate:

426,500 mol × 100 g/mol  = 42,650,000 g = 42,650 kg

Mass of  magnesium ion in V = 14.8 mg/L\times 3.637\times 10^8 L

= 5.382\times 10^{9} mg

=  5.382\times 10^{6} g

Moles of magnesium ions = \frac{5.382\times 10^{6} g}{24 g/mol}=224,250 mol

From 1 mole of magnesium ion 1 mol of magnesium hydroxide is formed . then from 224,250 moles of magnesium ion will form :

\frac{1}{1}\times 224,250 mol=224,250 mol of magnesium hydroxide

Mass of 224,250 moles of magnesium hydroxide:

224,250 mol × 58 g/mol  = 13,006,500 g = 13,006.5 kg

42,650 kg of calcium carbonate will be produced everyday.

13,600.5 kg of magnesium hydroxide will be produced everyday.

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3 years ago
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slippery, high pH, and caustic (last option)

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