Reactants left products right
Answer is: there is 2,69·10²³ atoms of bromine.
m(CH₂Br₂) = 39,0 g.
n(CH₂Br₂) = m(CH₂Br₂) ÷ M(CH₂Br₂).
n(CH₂Br₂) = 39 g ÷ 173,83 g/mol.
n(CH₂Br₂) = 0,224 mol.
In one molecule of CH₂Br₂, there is two bromine atoms, so:
n(CH₂Br₂) : n(Br) = 1 : 2.
n(Br) = 0,448 mol.
N(Br) = n(Br) · Na.
N(Br) = 0,448 mol · 6,022·10²³ 1/mol.
n(Br) = 2,69·10²³.
Answer:
molecular formulas of the hydrocarbons
Answer:
0.1113 mol
Explanation:
Data Given:
no. of atoms of CH₄= 6.70 x 10²² atoms
no. of moles of methane (CH₄) = ?
Solution:
we will find no. of moles of methane (CH₄)
Formula used
no. of moles = no. of atoms / Avogadro's number
Where
Avogadro's number = 6.022 x 10²³
Put values in above equation
no. of moles = 6.70 x 10²² atoms / 6.022 x 10²³ (atoms/mol)
no. of moles = 0.1113 mol
So,
There are 0.1113 moles of methane.
<h3>What is spectrometric method?</h3>
- A technique called spectrophotometry uses light intensity measurements as a beam of light travels through a sample solution to determine how much a chemical compound absorbs light.
- Every chemical either absorbs or transmits light across a specific spectrum of wavelengths, according to the fundamental principle.
- There are two main techniques used among the various forms of spectrophotometry:
- ultraviolet-visible range spectrophotometry, which examines the reflectance of certain spectra,
- and absorption spectrophotometry, which examines the absorption of radiation and particular spectra of light.
- Applications of spectrophotometry are useful for determining how well gases, liquids, and solids transmit, reflect, and absorb light.
Learn more about spectrometric method here:
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