What are some common tools scientists use to measure length and mass?
1 answer:
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Answer:
13.4mol of Mg
Explanation:
Given parameters:
Mass of magnesium = 321g
Unknown:
Number of moles = ?
Solution:
The number of moles of a substance is given as;
Number of moles =
Molar mass of Mg = 24g/mol
Insert the parameters and solve;
Number of moles = = 13.4mol of Mg
Answer:
The empirical formula is =
The formula of Valproic acid =
Explanation:
Mass of water obtained = 0.166 g
Molar mass of water = 18 g/mol
Moles of = 0.166 g /18 g/mol = 0.00922 moles
2 moles of hydrogen atoms are present in 1 mole of water. So,
<u>Moles of H = 2 x 0.00922 = 0.01844 moles </u>
Molar mass of H atom = 1.008 g/mol
<u>Mass of H in molecule = 0.01844 x 1.008 = 0.018588 g </u>
Mass of carbon dioxide obtained = 0.403 g
Molar mass of carbon dioxide = 44.01 g/mol
Moles of = 0.403 g /44.01 g/mol = 0.009157 moles
1 mole of carbon atoms are present in 1 mole of carbon dioxide. So,
<u>Moles of C = 0.009157 moles </u>
Molar mass of C atom = 12.0107 g/mol
<u>Mass of C in molecule = 0.009157 x 12.0107 = 0.11 g </u>
<u>Given that the Valproic acid only contains hydrogen, oxygen and carbon. </u>So,
Mass of O in the sample = Total mass - Mass of C - Mass of H
Mass of the sample = 0.165 g
<u>Mass of O in sample = 0.165 - 0.11 - 0.018588 = 0.036412 g </u>
Molar mass of O = 15.999 g/mol
<u>Moles of O = 0.036412 / 15.999 = 0.002276 moles</u>
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<u>Taking the simplest ratio for H, O and C as: </u>
<u>0.01844 : 0.002276 : 0.009157</u>
<u> = 8 : 1 : 4</u>
The empirical formula is =
Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.
Thus,
Molecular mass = n × Empirical mass
Where, n is any positive number from 1, 2, 3...
Mass from the Empirical formula = 4×12 + 8×1 + 16= 72 g/mol
Molar mass = 144 g/mol
So,
Molecular mass = n × Empirical mass
144 = n × 72
<u>⇒ n = 2</u>
The formula of Valproic acid =