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suter [353]
3 years ago
9

You are tossing a ball directly up into the air. Before the ball leaves your hand, you are exerting a force directed against the

force of gravity. If you apply a net force of 10 N to a 1 kg ball, what is the normal force acting on the ball?
Physics
1 answer:
DaniilM [7]3 years ago
7 0

Answer:

F n = 0.2 N

Explanation:

given,                                      

you are exerting force of 10 N on the ball.

mass of the ball = 1 kg              

acceleration due to gravity  = 9.8 m/s²

normal force on the ball = ?          

normal force is force exerted by the object to counteract the force from other object.                

normal force acting on the ball will be

F n = F - mg                          

F n = 10 - 1 × 9.8                        

F n = 10 -9.8                    

F n = 0.2 N            

Hence, normal force acting on the ball is equal to 0.2 N

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vredina [299]

Answer:

1. 38,500

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Explanation:

This would require a calculator. To find momentum, you multiply mass and velocity. You always want your mass to be measure in kilograms, but that is irrelevant in this question because they already are, it is just something to remember.

4 0
3 years ago
A 2.0kg rock is thrown straight up into the air with a speed of 30m/s. Ignore air resistance. What is the net force acting on th
bazaltina [42]

Answer:

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Explanation:

Given parameters:

Mass of rock = 2kg

Speed  = 30m/s

Unknown:

Net force on the rock  = ?

Solution:

The net force acting on this rock is a function of the acceleration due to gravity acting upon it.

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6 0
3 years ago
If an airplane traveled 1800 km in 2 hours<br> what is its average speed
Vesnalui [34]

Answer:

900km h

Explanation:

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8 0
2 years ago
A honeybee with a mass of 0.150 g lands on one end of a floating 4.75-g popsicle stick, as shown in (Figure 1) . After sitting a
Alekssandra [29.7K]

Answer:

0.0443 m/s

Explanation:

m_1 = Mass of honeybee = 0.15 g

m_2 = Mass of popsicle stick = 4.75 g

v_1 = Velocity of honeybee

v_2 = Velocity of stick = 0.14 cm/s

In this system the linear momentum is conserved

m_1v_1=m_2v_2\\\Rightarrow v_1=\dfrac{m_2v_2}{m_1}\\\Rightarrow v_1=\dfrac{4.75\times 0.14}{0.15}\\\Rightarrow v_1=4.43\ m/s

The velocity of the bee is 4.43 cm/s or 0.0443 m/s

5 0
3 years ago
8. Express 2.69 x 10^9 in standard form.
taurus [48]

Answer:

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Explanation:

10 x 9 equals 90

2.69 x 90 = 242.1

5 0
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