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suter [353]
3 years ago
9

You are tossing a ball directly up into the air. Before the ball leaves your hand, you are exerting a force directed against the

force of gravity. If you apply a net force of 10 N to a 1 kg ball, what is the normal force acting on the ball?
Physics
1 answer:
DaniilM [7]3 years ago
7 0

Answer:

F n = 0.2 N

Explanation:

given,                                      

you are exerting force of 10 N on the ball.

mass of the ball = 1 kg              

acceleration due to gravity  = 9.8 m/s²

normal force on the ball = ?          

normal force is force exerted by the object to counteract the force from other object.                

normal force acting on the ball will be

F n = F - mg                          

F n = 10 - 1 × 9.8                        

F n = 10 -9.8                    

F n = 0.2 N            

Hence, normal force acting on the ball is equal to 0.2 N

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Which conditions are usually the effect of a low air pressure system?
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3 0
2 years ago
How high can a 40 N force move a load, when 395 J of work is done?
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9.875

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w=f×s

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7 0
3 years ago
An extreme skier, starting from rest, coasts down a mountain slope that makes an angle of 25.0 with the horizontal. The coeffici
uranmaximum [27]

Answer:

V = 10.88 m/s

Explanation:

V_i =initial velocity = 0m/s

a= acceleration= gsinθ-\mu_kcosθ

putting values we get

a= 9.8sin25-0.2cos25= 2.4 m/s^2

v_f= final velocity and d= displacement along the inclined plane = 10.4 m

using the equation

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(0.5) m V_f^2 + mgh = (0.5) m V^2

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V = 10.88 m/s

6 0
3 years ago
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