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alexgriva [62]
3 years ago
12

In the early 1900s many scientists thought that an atom consisted of a positive substance with negative charges scattered throug

hout the substance. Then Ernest Rutherford completed an experiment that changed the concept of an atom. His discovery led to the understanding that an atom consists mostly of empty space with —
Physics
1 answer:
antiseptic1488 [7]3 years ago
3 0

Answer:

Rutherford's gold foil experiment showed that the atom is mostly empty space with a tiny, dense, positively-charged nucleus. Based on these results, Rutherford proposed the nuclear model of the atom.

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Genevieve was working on a science lab. In her lab, she was combining two chemicals and timing how long the reaction took to for
dexar [7]

Answer: Her test trials had a high level of accuracy but a low level of precision.

Explanation:

5 0
3 years ago
A 91.5 kg football player running east at 3.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft
PIT_PIT [208]

Their velocity afterward is  v=3.467 m/s

Explanation:

Given:

Mass of the first football player= 91.5 kg

Initial velocity of the football player 3.73 m/s

Mass of second football player=63.56 kg

Initial velocity of the second football player=3.09 m/s

To find:

Final velocity of both players=?

Solution:

According to the law of conservation of momentum,

Initial momentum =final momentum

mathematically represented as  

m_1u_1+m_2u_2=m_1v_1+m_2v_2...........................(1)

where

u_1=intial velocity of the football player

u_2 = inital velocity of second football player

v_1=finall velocity of the  first football player

v_2=final velocity of second football player

after tackling , both the football players moves with the same velocity,

so v_1=v_2=v

Hence equation (1) becomes

m_1u_1+m_2u_2=(m_1+m_2)v

v=\frac{m_1u_1+m_2u_2}{(m_1+m_2)}

now substituting the values,

v=\frac{(91.5\times+3.73)+(63.5\times3.09)}{(91.5+63.5)}v=\frac{(341.29+196.210)}{155}

v=\frac{537.5}{155}

v=3.467 m/s

7 0
3 years ago
in a human cannonball a person is shot from a cannon with a barrel that is 3.05 m long. 16700 J of work are done to accelerate t
ankoles [38]
The work done to accelerate the acrobat is given by
W=Fd
where F is the force applied and d the distance of application of the force.
If the barrel is 3.05 m long, then d=3.05 m. Therefore we can find the force:
F= \frac{W}{d} = \frac{17600 J}{3.05 m} =5475 N
6 0
3 years ago
Two cars, one of mass 1300 kg, and the second of mass 2400 kg, are moving at right angles to each other when they collide and st
Margarita [4]

To solve this problem we will apply the momentum conservation theorem, that is, the initial momentum of the bodies must be the same final momentum of the bodies. The value that will be obtained will be a vector value of the final speed of which the magnitude will be found later. Our values are given as,

m_1 = 1300kg

m_2 = 2400kg

u_1 = 12m/s i

u_2 = 18m/s j

Using conservation of momentum,

m_1u_1+m_2u_2 = (m_1+m_2)v_f

1300*12i-2400*18j = (1300+2400)v_f

Solving for v_f

v_f = 4.2162i-11.6756j

Using the properties of vectors to find the magnitude we have,

|v| = \sqrt{(4.2162^2)+(-11.6756)^2}

|v| = 12.4135m/s

Therefore the magnitude of the velocity of the wreckage of the two cars immediately after the collision is 12.4135m/s

6 0
2 years ago
The mass of earth 6*10^24kg its radius is 6.4*10^3km now calculate due to gravity on earth<br>​
irga5000 [103]

Answer:

Explanation:

in your textbook, they have a formula like this:

g=mass of earth*G/R^2

G=6.67*10^-11

apply to this

we have g=6*10^2*4*6.67*10^-11/(6.4*10^3*1000)^2=9.78

7 0
2 years ago
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