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aleksandr82 [10.1K]
3 years ago
8

How many moles of 0.225 M CaOH2 are present in 0.350 L of solution?

Chemistry
1 answer:
weeeeeb [17]3 years ago
7 0

Answer : The number of moles of solute Ca(OH)_2 is, 0.0788 moles.

Explanation : Given,

Molarity = 0.225 M

Volume of solution = 0.350 L

Formula used:

\text{Molarity}=\frac{\text{Moles of }Ca(OH)_2}{\text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

0.225M=\frac{\text{Moles of }Ca(OH)_2}{0.350L}

\text{Moles of }Ca(OH)_2=0.0788mol

Therefore, the number of moles of solute Ca(OH)_2 is, 0.0788 moles.

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ch4aika [34]

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MgCO₃

Explanation:

From the question given above, we obtained:

MgF₂ + Li₂CO₃ —> __ + 2LiF

The missing part of the equation can be obtained by writing the ionic equation for the reaction between MgF₂ and Li₂CO₃. This is illustrated below:

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MgF₂ + Li₂CO₃ —>

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MgF₂ + Li₂CO₃ —> MgCO₃ + 2LiF

Now, we share compare the above equation with the one given in the question above to obtain the missing part. This is illustrated below:

MgF₂ + Li₂CO₃ —> __ + 2LiF

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3 years ago
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Answer:

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Explanation:

The weights of all elements are always compared to the Carbon-12 because the mass of carbon is 12 which is the exactly the sum of protons and neutrons.  

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shepuryov [24]

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