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Bess [88]
3 years ago
9

Una muestra de 2,5000 (g) de piedra caliza, se disuelve y se precipita el Calcio como oxalato de Calcio (CaC2O4), este precipita

do se calcina transformándose en Carbonato de Calcio (CaCO3). El peso de este compuesto es de 1,2093 (g). Calcular el % de Calcio en la muestra
Chemistry
1 answer:
sergij07 [2.7K]3 years ago
4 0

Answer:

\%Ca=19.378\%

Explanation:

¡Hola!

En este caso, basado en la información dada, es posible conocer la masa de calcio en carbonato de calcio, que de hecho es la misma en la muestra, al utilizar el siguiente esquema de cálculo:

m_{Ca}=1,2093gCaCO_3*\frac{1molCaCO_3}{100.1gCaCO_3}*\frac{1molCa}{1molCaCO_3}*\frac{40.1gCa}{1molCa}\\\\m_{Ca}=0.48444gCa

Finalmente, calculamos el porcentaje requerido como sigue:

\% Ca=\frac{0.48444g}{2.5000g} *100\%\\\\\%Ca=19.378\%

¡Saludos!

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Answer:

The % yield is 74.45 %

Explanation:

<u>Step 1:</u> The balanced equation

C6H12O6⟶2CH3CH2OH+2CO2

<u>Step 2</u>: Data given

Molar mass glucose = 180.15 g/mol

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Molar mass of carbon dioxide = 44.01 g/mol

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<u>Step 3:</u> Calculate moles of glucose

Moles glucose = Mass glucose  / Molar mass of glucose

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7 0
3 years ago
Which two changes would make this reaction reactant-favored?
Vera_Pavlovna [14]

Two changes would make this reaction reactant-favored

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<h3>Further explanation</h3>

Given

Reaction

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Required

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