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Oksi-84 [34.3K]
3 years ago
6

tom ran a complete mile. sarah ran half of that. mike ran half of what sarah ran and lisa ran half of what mike ran. what part o

f the did lisa run? show work please
Mathematics
1 answer:
KiRa [710]3 years ago
3 0
1/2 = .5 /2 =.25 / 2 = .125
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Simplify 3^0. Simplified form: ______
Shkiper50 [21]

Answer:

1

Step-by-step explanation:

3^0

Apply rule a^0=1 a=0

=1

Thanks for letting me help!!

6 0
4 years ago
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In the fallowing diagram, it is shown that mEHG is a right angle, mEHF = x+ 1 and mGHF = 5x+5. Find the value of x, the numerica
GalinKa [24]

Answer:

x = 14

EHF = 15 degree  GHF = 75 degree  

Step-by-step explanation:

(x+1) + (5x+5) = 90

(x+5x)+ (1+5) = 90

6x + 6 = 90

6x = 90-6

6x = 84

x = 84/6

x = 14

EHF + GHF = 90 degree

EHF = x+1

       = 14 + 1 = 15

       = 15 degree

GHF = 5x+5

        = 14 x  5 (+5) = 70 + 5

        = 75 degree

EHF = 15 degree  GHF = 75 degree  

4 0
3 years ago
Calls to a customer service center last on average 2.8 minutes with a standard deviation of 1.4 minutes. An operator in the call
Natali5045456 [20]

Answer:

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n-values of normal variable:

Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is M = n\mu and the standard deviation is s = \sigma\sqrt{n}

Calls to a customer service center last on average 2.8 minutes.

This means that \mu = 2.8

75 calls each day.

This means that n = 75

What is the expected total amount of time in minutes the operator will spend on the calls each day

This is M, so:

M = n\mu = 75*2.8 = 210

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

6 0
3 years ago
Stan spent $440 on 8 chairs. To find out how much he
djverab [1.8K]

Answer:

the answer is there should be another digit in the quotient

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3 years ago
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The elevation of sea is about 510 feet below sea level what integer represents this elevation
Taya2010 [7]

Answer:

-510

Step-by-step explanation:

Below the sea level should be represented by negative sign.

So,  -510

3 0
3 years ago
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