Answer:
It gives you 28 different 10-digit numbers
Step-by-step explanation:
The leftmost position digit can not be 0 --- hence, it is 1, since there is no other possibilities.
The rightmost position (the "ones" position) must be 0 to provide an even number.
Hence, you have 8 remaining positions to fill with six ones and two zeros by an arbitrary way.
You can place two digits of zero among 8 positions by 
= 
different ways = 4*7 = 28 different ways,
<span>An arithmetic sequence is a sequence with the difference between two consecutive terms constant. The difference is called the common difference.<span>A geometric sequence is a sequence with the ratio between two consecutive terms constant.</span></span>
The answer should be J.15.
Let
n-------> the number of nickels
q------> the number of quarters
we know that
so
----> equation A
----> equation B
substitute equation B in equation A
![0.05n+0.25[3n]=1.60](https://tex.z-dn.net/?f=0.05n%2B0.25%5B3n%5D%3D1.60)
Find the value of q
therefore
<u>The answer part a) is</u>
the number of nickels are 
and the number of quarters are 
<u>the answer Part b) is</u>
The expressions that represents the number of quarters is
well L x W x H = 448³ x 12 x 8 = <span>2<span>²³
so your answer is 2²³</span></span>
