Ask question

Ask question

All categories

3 years ago

8

Which of the following is not a stage in the development of a thunderstorm? developing stage dissipating stage mature stage updr

aft stage

1 answer:

mars1129 [50]3 years ago

8 0

The answer is: Mature stage

You might be interested in

A container of oxygen with a fixed volume has a pressure of 13.0 atm at a temperature of 20 °C. What will the pressure of the ox

Norma-Jean [14]

Given:

P1 = 13.0 atm

T1 = 20 °C

T2 = 102 °C

Required:

P2 of oxygen

Solution:

At constant volume, we can apply Gay-Lussac’s law of pressure and temperature relationship

P1/T1=P2/T2

(13.0 atm) / (20 °C) = P2 / (102 °C)

P2 = 66.3 atm

The answer is not in the choices given.

6 0

3 years ago

Plant cell synthesize energy rich organic molecules and later energy is released through the processes of

zmey [24]

Pretty sure its photosynthesis ?

7 0

3 years ago

β‑Galactosidase (β‑gal) is a hydrolase enzyme that catalyzes the hydrolysis of β‑galactosides into monosaccharides. A 0.387 g sa

gtnhenbr [62]

Answer:

The molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=icRT$

where,

$\pi$ = osmotic pressure of the solution = 0.602 mbar = 0.000602 bar

0.000602 bar = 0.000594 atm

(1 atm = 1.01325 bar)

i = Van't hoff factor = 1 (for non-electrolytes)

c = concentration of solute = ?

R = Gas constant = $0.0820\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273.15 +25]=298.15 K$

Putting values in above equation, we get:

$0.000594 atm=1\times c\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298.15 K\\\\c=2.4278\times 10^{-5} mol/L$

The concentration of solute is $2.4278\times 10^{-5} mol/L$

Volume of the solution = V =0.137 L

Moles of β‑Galactosidase = n

$C=\frac{n}{V(L)}$

$n=2.4278\times 10^{-5} mol/L\times 0.137 L$

$n=3.3261\times 10^{-6} mol$

To calculate the molecular mass of solute, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of β‑Galactosidase = $3.3261\times 10^{-6} mol$

Given mass of β‑Galactosidase= 0.387 g

Putting values in above equation, we get:

$3.3261\times 10^{-6} mol =\frac{0.387 g}{\text{Molar mass of solute}}\\\\\text{Molar mass of solute}=116,352.97 g/mol$

Hence, the molar mass of unknown β‑Galactosidaseis 116,352.97 g/mol.

3 0

3 years ago

In a similar analysis, a student determined that the percent of water in the hydrate was 25.3%. the instructor informed the stud

Oxana [17]

Answer is: f<span>ormula for the hydrated compound is CuSO</span>₄·3H₂O.
ω(H₂O) = 25,3% = 0,253.
ω(CuSO₄) = 100% - 25,3%.
ω(CuSO₄) = 74,7% = 0,747.
ω(H₂O) : M(H₂O) = ω(CuSO₄) : M(CuSO₄).
0,253 : M(H₂O) = 0,747 : 159,6 g/mol.
M(H₂O) = (0,253 · 159,6 g/mol) ÷ 0,747.
M(H₂O) = 54 g/mol.
N(H₂O) = 54 g/mol ÷ 18 g/mol.
N(H₂O) = 3.

5 0

3 years ago

Read 2 more answers

Did education decline during the Renaissance

spin [16.1K]

No, education actually increased during the Renaissance. It was a time where people were discovering the philosophical nature of things, and were putting it into writing and such. The Renaissance was a time period where more and more people considered introspective ideas and more people studied topics such as art, science, mathematics, technology, music, and warfare.

3 0

3 years ago