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saw5 [17]
3 years ago
5

What is catalyst? Write its types.​

Chemistry
2 answers:
ella [17]3 years ago
6 0

Answer:

A catalyst is a chemical substance thatalters therate of chemical reactions not consumed by the reactions.

Step2247 [10]3 years ago
5 0

Answer:

A catalyst is a chemical substance that alters the rate of chemical reaction not consumed by the reaction. Hence, a catalyst can be recovered chen unchanged at the ends of chemical reaction. Catalyst can be divided into two typ the basis whether it speeds up or slowdowns the rate of chemical reaction. The positive catalyst and negative catalyst.

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Hello! Can you please help me with this because I don’t get it at all. Thanks.
denpristay [2]

Answer:

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Explanation:

4 0
3 years ago
Read 2 more answers
Which of the following has the highest pH?
Tema [17]

Answer:

D

Explanation:

pH=-log(x)

x=0.001M,pH=3

x=0.01M,pH=2

x=0.1M,pH=1

x=1M,pH=0

Highest pH is for option D

7 0
3 years ago
Read 2 more answers
Enter your answer in the provided box.
Lina20 [59]

Answer:

5.06atm

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (Litres)

V2 = final volume (Litres)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

P1 = 1.34 atm

P2 = ?

V1 = 5.48 L

V2 = 1.32 L

T1 = 61 °C = 61 + 273 = 334K

T2 = 31 °C = 31 + 273 = 304K

Using P1V1/T1 = P2V2/T2

1.34 × 5.48/334 = P2 × 1.32/304

7.34/334 = 1.32P2/304

Cross multiply

334 × 1.32P2 = 304 × 7.34

440.88P2 = 2231.36

P2 = 2231.36/440.88

P2 = 5.06

The final pressure is 5.06atm

6 0
3 years ago
Need to complete the chart
GalinKa [24]

Answer:

Row 1

[H^+]=1.8\times 10^{-6}M

pH=-\log[H^+]=-\log[1.8\times 10^{-6}]=5.7

pOh=14-pH=14-5.7=8.3

pOH=-\log[OH^-]

[OH^-]=0.5\times 10^{-8}M

Hence, acidic

Row 2

[OH^-]=3.6\times 10^{-10}M

pOH=-\log[OH^-]=-\log[3.6\times 10^{-10}]=9.4

pH=14-pOH=14 - 9.4 = 4.6

pH=-\log[H^+]

[H^+]=2.6\times 10^{-5}M

Hence, acidic

Row 3

pH = 8.15

[H^+]=0.7\times 10^{-8}M

pOH=14-pH=14 - 8.15 = 5.8

pOH=-\log[OH^-]

[OH^-]=1.5\times 10^{-6}M

Hence, basic

Row 4

pOH = 5.70

[OH^-]=1.8\times 10^{-6}M

pH=14-pOH=14 - 5.70 = 8.3

pH=-\log[H^+]

[H^+]=0.5\times 10^{-8}M

Hence, basic



3 0
3 years ago
Convert 25 gram of carbon dioxide to mold
Rus_ich [418]

The atomic weight of carbon dioxide is about 12.011 + 15.999 + 15.999 = 44.009.

44.009 grams of CO2 = 1 mole of CO2             CO2 = Carbon dioxide

25 ÷ 44.009 ≈ 0.568

About 0.568 moles of CO2

7 0
3 years ago
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