4. An archer pulls a bowstring back 0.440 m, and the spring constant of the bow is 545 N/m.

Physics

1 answer:

mixer [17]2 years ago

3 0

Answer: (a)part:545nm multiply by 0.440m=239.8JEWELS(J)

(B):1/2MULTIPLY BY MVSQUARE(APPLY THE FORMULA OF KINETIC ENERGY)REARANGE THE FORMULA,V=2.13MS

Explanation:

SO FOR PART A, IN ORDER TO CALCULATE THE WORK DONE YOUR SUPPOSE TO APPLY THE FORMULA FORCE MULTIPLY BY DISTANCE WHICH IS THE FORMULA FOR WORK DONE,IN THIS SCENARIO YOU HAD A FORCE OF 545NM AND A DISANCE OF 0.440,SO I ORDER TO FIND THE WORK DONE WE MULTIPLIED THEM BOTHE ACCORDING TO THE FORMULA AND GOT THE ANSWER.

FOR PARTB,I JUST SIMPLY APPLIED THE FORMULA FOR KINETIC ENERGY AND SIMPLY REARRANGED IT IN ORDER TO FIND THE VELOCITY.I MADE V THE SUBJECT OF THE FORMULA.

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