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2 years ago

4. An archer pulls a bowstring back 0.440 m, and the spring constant of the bow is 545 N/m.

Physics

1 answer:

mixer [17]2 years ago

3 0

Answer: (a)part:545nm multiply by 0.440m=239.8JEWELS(J)

(B):1/2MULTIPLY BY MVSQUARE(APPLY THE FORMULA OF KINETIC ENERGY)REARANGE THE FORMULA,V=2.13MS

Explanation:

SO FOR PART A, IN ORDER TO CALCULATE THE WORK DONE YOUR SUPPOSE TO APPLY THE FORMULA FORCE MULTIPLY BY DISTANCE WHICH IS THE FORMULA FOR WORK DONE,IN THIS SCENARIO YOU HAD A FORCE OF 545NM AND A DISANCE OF 0.440,SO I ORDER TO FIND THE WORK DONE WE MULTIPLIED THEM BOTHE ACCORDING TO THE FORMULA AND GOT THE ANSWER.

FOR PARTB,I JUST SIMPLY APPLIED THE FORMULA FOR KINETIC ENERGY AND SIMPLY REARRANGED IT IN ORDER TO FIND THE VELOCITY.I MADE V THE SUBJECT OF THE FORMULA.

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A body of mass 5.0 kg is suspended by a spring which stretches 10 cm when the mass is attached. It is then displaced downward an

Dominik [7]

Answer:

position as a function of time is y = 0.05 × cos(9.9)t

Explanation:

given data

mass = 5 kg

length = 10 cm = 0.1 m

displaced = 5 cm

to find out

position as a function of time

solution

we will apply here equilibrium that is

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put here value and find k

k = $\frac{5*9.8}{.01}$

k = 490 N/m

and ω is

ω = $\sqrt{\frac{k}{m} }$

ω = $\sqrt{\frac{490}{5} }$

ω = 9.9

so here position w.r.t time is

y = 0.05 × cosωt

y = 0.05 × cos(9.9)t

so position as a function of time is y = 0.05 × cos(9.9)t

8 0

3 years ago

If a car is moving to the left with constantvelocity, one can conclude thatthere mustbe no forces applied to the car.the netforc

laila [671]

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Explanation:

Given

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3 years ago

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Answer:

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3 years ago

A uniform thin rod of mass ????=3.41 kg pivots about an axis through its center and perpendicular to its length. Two small bodie

vivado [14]

Answer:

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Explanation:

The Diagram for this question is gotten from the first uploaded image

From the question we are told that

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The mass of each small bodies is $m = 0.249 \ kg$

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And $I_m$ the moment of inertia of the two small bodies which (from the diagram can be assumed as two small spheres) can be mathematically represented as