4. An archer pulls a bowstring back 0.440 m, and the spring constant of the bow is 545 N/m.
1 answer:
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Answer:
θ = 20.9 rad
Explanation:
In a blender after a short period of acceleration the blade is kept at a constant angular velocity, for which we can use the relationship
w = θ / t
θ = w t
if we know the value of the angular velocity we can find the angular position, we must remember that all the angles must be in radians
suppose that the angular velocity is w = 10 rpm, let us reduce to the SI system
w = 10 rpm
= 1,047 rads
let's calculate
θ = 1,047 20
θ = 20.9 rad
Explanation:
Consider the kinematic equation,
where x is the distance traveled, v is the initial velocity, a is the acceleration and t is time. By plugging in known values and solving for x,
through simple algebra we get
where this is the distance traveled in meters.