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victus00 [196]
3 years ago
14

Velocity profile of a moving fluid over a flat (fixed) plate is given as: ???????? = from the fixed plate (yy = 0) in mm, u is t

he velocity in xx direction in mm/????????. Calculate the shear stress on the fluid at yy = 0.15 m if the viscosity of the fluid 8.6 poise (1 Poise= 1 ????????yy????????????????.????????) cccc2

Physics
1 answer:
schepotkina [342]3 years ago
8 0

Answer: The question has some details missing which is the velocity profile .The velocity profile is given as u = (8y - 0.3y^2) mm/s

the shear stress on the fluid at y = 0.15 m = 6.80 x 10^-3N/m^2

Explanation:

The detailed steps is the use of the relationship between the shear stress, viscosity and the velocity profile. appropriate differentiation and substitution were made to calculate the shear stress as is shown in the attachment.

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In three to five sentences, identify two components of the control subsystem of a vehicle, and use them to explain why driving c
vredina [299]

A car is built from various subsystems. If these subsystems are not working properly it is dangerous because it can cause a serious traffic accident.

<h3>What subsystems do cars have?</h3>

When you're testing the build of a car, you have to check its many subsystems:

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<h3>Why is a car with damaged subsystems dangerous?</h3>

The subsystems of a car are very important components that allow the proper functioning of the car. These subsystems work synchronously making the car work properly.

However, if one of these subsystems is not working properly it could cause a malfunction that could lead to a traffic accident.

Learn more about cars in: brainly.com/question/11733094

7 0
2 years ago
A plane has a mass of 360,000 kg takes-off at a speed of 300 km/hr. i) What should be the minimum acceleration to take off if th
melomori [17]

Answer:

i) the minimum acceleration to take off is 22500 km/h²

ii) the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) required force that the engine must exert to attain acceleration is 625 kN

Explanation:

Given the data in the question;

mass of plane m = 360,000 kg

take of speed v = 300 km/hr = 83.33 m/s

i)

What should be the minimum acceleration to take off if the length of the runway is 2.00 km

from Newton's equation of motion;

v² = u² + 2as

we know that a plane starts from rest, so; u = 0

given that distance S = 2 km

we substitute

(300)² = 0² + ( 2 × a × 2 )

90000 = 4 × a

a = 90000 / 4

a = 22500 km/h²

Therefore,  the minimum acceleration to take off is 22500 km/h²

ii) At this acceleration, how much time would the plane need from starting to takeoff.

from Newton's equation of motion;

v = u + at

we substitute

300 = 0 + 22500 × t

t = 300 / 22500

t = 0.0133 hrs

Therefore, the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) What force must the engines exert to attain this acceleration

we know that;

F = ma

acceleration a = 22500 km/hr² = 1.736 m/s²

so we substitute

F = 360,000 kg × 1.736 m/s²

F =  624960 N

F = 625 kN

Therefore, required force that the engine must exert to attain acceleration is 625 kN

5 0
3 years ago
Winds blowing toward the east are called easterlies.<br><br><br> True or False
eimsori [14]

Answer: False

Explanation:

Winds are named for the cardinal direction they blow from.  Hence, a wind that <em>"blows towards the east"</em>, logically should <u>come from the west </u>and is called a <em>"west wind"</em>.

In thise sense, one of the best examples of this type of wind are the <em>Westerlies</em>, which are are prevailing winds that blow from the west at midlatitudes and have the characteristic that are stronger during winter and weaker during summer.

Therefore, the statement is false.

6 0
3 years ago
A coil of 150 turns of wire is in the form of a circle of radius 7.5 cm, and sits in the center of a dipole magnet that produces
irga5000 [103]

Answer:

Current in the loop is 0.063 A        

Explanation:

Number of turns in the coil N = 150

Radius of the circular loop r = 7.5 cm = 0.075 m

So area A=\pi r^2=3.14\times 0.075^2=0.0176m^2

Magnetic field B = 1.5 T

Maximum torque is given \tau =0.25Nm

We have to find current in the coil

Torque on circular coil in magnetic field is equal to

\tau =BINA

0.25=1.5\times I\times 150\times 0.0176

I = 0.063 A

7 0
3 years ago
Can someone give me some tips of how to study. I have already tried writing everything in my lesson but it doesn't seem to work
larisa [96]
Highlighter, color coding sections that go together, flash cards, relaxing with someone while they read out questions ( this will help with testing anxiety too). If you get distracted easily use games to study or small sayings instead of the usual white and black sheet of paper.
3 0
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