Answer:
time to fall is 3.914 seconds
Explanation:
given data
half distance time = 1.50 s
to find out
find the total time of its fall
solution
we consider here s is total distance
so equation of motion for distance
s = ut + 0.5 × at² .........1
here s is distance and u is initial speed that is 0 and a is acceleration due to gravity = 9.8 and t is time
so for last 1.5 sec distance is 0.5 of its distance so equation will be
0.5 s = 0 + 0.5 × (9.8) × ( t - 1.5)² ........................1
and
velocity will be
v = u + at
so velocity v = 0+ 9.8(t-1.5) ..................2
so first we find time
0.5 × (9.8) × ( t - 1.5)² = 9.8(t-1.5) + 0.5 ( 9.8)
solve and we get t
t = 3.37 s
so time to fall is 3.914 seconds
p=F/S=>S=F/p=5*10³/12=416.66 m²
Explanation:
<h3>We have for velocity of package v= 20 - 9.8t and for distance from the ground y = h + 20t - 4.9t2.</h3><h3>We have y = 0 and t = 18.0 s we have h = 4.9·182 - 20·18 = 1227.6 m.</h3><h3>Velocity at landing v = 20 - 9.8·18 = - 156.4 m/s </h3>
Kinetic friction, for example, generally turns energy into heat, and although we associate kinetic friction with energy loss, it really is just a way of transforming kinetic energy into thermal energy. The law of conservation of energy applies always, everywhere, in any situation. ?
