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Archy [21]
3 years ago
9

A 115-turn circular coil of radius 2.71 cm is immersed in a uniform magnetic field that is perpendicular to the plane of the coi

l. During 0.133 s the magnetic field strength increases from 50.1 mT to 90.5 mT. Find the magnitude of the average EMF, in millivolts, that is induced in the coil during this time interval.
Physics
1 answer:
tester [92]3 years ago
3 0

Answer:

80.6 mV

Explanation:

Parameters given:

Number of turns, N = 115

Radius of coil, r = 2.71 cm = 0.0271m

Time taken, t = 0.133s

Initial magnetic field, Bin = 50.1 mT = 0.0501 T

Final magnetic field, Bfin = 90.5 mT = 0.0905 T

Induces EMF is given as:

EMF = [(Bfin - Bin) * N * A] / t

EMF = [(0.0905 - 0.0501) * 115 * pi * 0.0271²] / 0.133

EMF = (0.0404 * 115 * 3.142 * 0.0007344) / 0.133

EMF = 0.0806 V = 80.6 mV

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Addiction, degradation of the body, and HIV infections. Hey, as long as it makes you feel happy, it doesn't matter that you're dying. Don't do drugs, kids.

5 0
3 years ago
Read 2 more answers
The rate constant for this first‑order reaction is 0.150 s−1 at 400 ∘C. A⟶products How long, in seconds, would it take for the c
Afina-wow [57]

Answer : The time taken for the concentration will be, 7.98 seconds

Explanation :

First order reaction : A reaction is said to be of first order if the rate is depend on the concentration of the reactants, that means the rate depends linearly on one reactant concentration.

Expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{[A]_o}{[A]}

where,

k = rate constant  = 0.150s^{-1}

t = time taken for the process  = ?

[A]_o = initial concentration = 0.860 M

[A] = concentration after time 't' = 0.260 M

Now put all the given values in above equation, we get:

0.150s^{-1}=\frac{2.303}{t}\log\frac{0.860}{0.260}

t=7.98s

Therefore, the time taken for the concentration will be, 7.98 seconds

6 0
3 years ago
Two boxers are fighting. Boxer 1 throws his 5 kg fist at boxer 2 with a speed of 9 m/s.
Sladkaya [172]

Answer:

0.001 s

Explanation:

The force applied on an object is equal to the rate of change of momentum of the object:

F=\frac{\Delta p}{\Delta t}

where

F is the force applied

\Delta p is the change in momentum

\Delta t is the time interval

The change in momentum can be written as

\Delta p=m(v-u)

where

m is the mass

v is the final velocity

u is the initial velocity

So the original equation can be written as

F=\frac{m(v-u)}{\Delta t}

In this problem:

m = 5 kg is the mass of the fist

u = 9 m/s is the initial velocity

v = 0 is the final velocity

F = -45,000 N is the force applied (negative because its direction is opposite to the motion)

Therefore, we can re-arrange the equation to solve for the time:

\Delta t=\frac{m(v-u)}{F}=\frac{(5)(0-9)}{-45,000}=0.001 s

4 0
3 years ago
An electron passes through two rectangular regions that contain uniform magnetic fields, B1 and B2. The field B1 is stronger tha
gtnhenbr [62]

Answer:

v1 = v2

Explanation:

Given:

- The missing figure is (attached).

- The Magnetic Field B1 > B2

Find:

How does the speed v1 of the electron in region 1 compare with the speed v2 in region 2?

Solution:

- From Lorentz Law we know that the Force that acts on the charge particle is the cross product of Magnetic Field Vector ( B1 or B2 ) and the velocity vector (v1 or v1).

- From the attached figure related to this problem we see that the electron velocity or direction of motion is always parallel to the magnetic field B1&B2.

- The law of cross product for parallel vector is 0. Hence, the Lorentz force acting on the electron is also zero.

- Zero Force means no work is done on the particle by the magnetic field, thus, the change in kinetic energy also zero for conservation of energy to hold.

- The initial and final kinetic energies of the electron is same. Hence, we can conclude that v1 = v2.

3 0
3 years ago
Any fracture or system of fractures along which Earth moves is known as a
Anton [14]
The answer should be B. Fault.

4 0
4 years ago
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