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leva [86]
3 years ago
14

What are two parts of an atom

Physics
1 answer:
seraphim [82]3 years ago
7 0

Answer:

Nucleus And electron cloud

Explanation:

Hope this helps

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What variables show a direct relationship? Check all that apply. the speed of a car and the distance traveled the elevation abov
Llana [10]
The variables that show a direct relationship are :
- The speed of a car and the distance traveled
- Number of students in  a cafeteria and the amount of food consumed
- The distance a planet is from the sun and that planet's temperature
- The mass of a space shuttle and its acceleration through space

In direct relationship, when one factor is increased/decreased , it will directly cause the other factor to be increased/decreased
3 0
3 years ago
Read 2 more answers
What is the voltage in a circuit if the current is 6.2 A and the resistance is 18 ohms?
Nitella [24]
We already know the formula:
Voltage = Current * Resistance
In the given question, there are numerous information's that are already given.
Current = 6.2 A
Resistance = 18 ohms
Then
Voltage = 6.2 * 18 Volts
             = 111.6 Volt
So, the voltage in the circuit will be 111.6 volts. I hope it helps you.
4 0
3 years ago
A car travels 20 km South, then turns and travels 30 km East? What is the total displacement?
Ne4ueva [31]

Answer:

Explanation:36.05 km

Given

First car travels r_1=20\ km South

then turns and travels r_2=30\ km east

Suppose south as negative y axis and east as positive x axis

So, r_1=-20\hat{j}

r_2=30\hat{i}

Displacement is the shortest between initial and final point

Dispalcement=r=r_1+r_2

Displacement=-20\hat{j}+30\hat{i}

Displacement=30\hat{i}-20\hat{j}

Magnitude =\sqrt{30^2+(-20)^2}

Magnitude=36.05\ km

4 0
3 years ago
1. A car with a mass of 2500 kg accelerates when the traffic light turns green. If the net force
soldier1979 [14.2K]

;Net force = mass of the body × acceleration of the body due to the net force

; 5000 = 2500 a...then divide both sides by 2500

; acceleration(a) = 2 m/s^2

5 0
3 years ago
(a) Calculate the self-inductance (in mH) of a 55.0 cm long, 10.0 cm diameter solenoid having 1000 loops.
DedPeter [7]

Explanation:

(a) We have,

Length of solenoid, l = 55 cm = 0.55 m

Diameter of the solenoid, d = 10 cm

Radius, r = 5 cm = 0.05 m

Number of loops in the solenoid is 1000.

(a) The self inductance in the solenoid is given by :

L=\dfrac{\mu_o N^2A}{l}

A is area

L=\dfrac{4\pi \times 10^{-7}\times (1000)^2\times \pi (0.05)^2}{0.55}\\\\L=0.0179\ H\\\\L=17.9\ mH

(b) The energy stored in the inductor is given by :

E=\dfrac{1}{2}LI^2\\\\E=\dfrac{1}{2}\times 0.0179\times (19.5)^2\\\\E=3.4\ J

Hence, this is the required solution.

4 0
3 years ago
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