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leva [86]
3 years ago
14

What are two parts of an atom

Physics
1 answer:
seraphim [82]3 years ago
7 0

Answer:

Nucleus And electron cloud

Explanation:

Hope this helps

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A rock band playing an outdoor concert produces sound at 120 dB 5.0 m away from their single working loudspeaker. What is the so
joja [24]

ANSWER:100dB

f<em>rom the  sound intensity level,the sound intensity is calculated as:</em>

<em />\beta<em>₁=</em>\beta<em>=(10dB)㏒₁₀(l₁/l₀)</em>

<em>inserting numbers:</em>

<em>120dB=(10dB)㏒₁₀[l₁/10⁻¹²W/m⁸] or 12=㏒₁₀[l₁/(10⁻¹²)W/m²</em>

<em>Getting the antilog of both sides and obtain 10¹²=l₁(10⁻¹²W/m²)which </em>

<em>can be used to solve for l₁ and get</em>

<em>          l₁=(10⁻¹²W/m²)(10¹²)=1 W/m²</em>

<em>since the sound  intensity is related to the power and that the power does not change,the sound intensity at any other point can be solved.Plugging-in</em>

<em>ᵃ = 4πr²,into P=l₁ₐ₁=l₂ₐ₂ and get:</em>

<em>l₂=l₁(r₁/r₂)² =(1W/m²)(5/35) =2.04×10⁻²W/m²</em>

<em>since we know the sound intensity at the sound point 2r,the sound intensity level at the point can be solved.We have:</em>

<em>     </em>\beta<em>₂=</em>\beta<em>=(10dB)㏒₁₀(l₂/l₀)=(10dB)㏒₁₀(2.04×10⁻²/1×10⁻²)</em>

<em>    </em>\beta<em>₂=(10dB)㏒₁₀(2.04×10¹⁰)</em>

<em />\beta<em> =(10dB)[㏒₁₀(2.04)+㏒₁₀(10¹⁰)]=10dB[0.32+10]=103dB=100dB</em>

<em />

3 0
3 years ago
A train having speed of 85 km/h takes 5 hours to travel from Kerala to Karnataka. Calculate the distance between Kerala and Karn
Morgarella [4.7K]

Answer:

the distance between Kerala and Karnataka is 425 km.

Explanation:

Given;

speed of the train, u = 85 km/h

time taken for the train to travel from Kerala to Karnataka, t = 5 hours

The distance between Kerala and Karnataka is calculated as;

Distance = speed x time

Distance = 85 km/h  x  5 h

Distance = 425 km

Therefore, the distance between Kerala and Karnataka is 425 km.

6 0
3 years ago
Identify two simple machines in this compound machine. A. screw, lever B. screw, incline plane C. double pulley D. lever, pulley
seropon [69]
It's A, the Screw leaver 
5 0
3 years ago
Read 2 more answers
Consider the field E1 in the dielectric on the left of this interface. E1= 3ax+4ay+5az The interface lies in the z=0 plane. Find
denpristay [2]

Answer:

E₂ = 3ax +4ay + 2az

Interface angles  ∅₁ = 45°

                           ∅₂ = 68.20°

Explanation:

See the attached files for the calculation

7 0
3 years ago
Suppose you are playing hockey on a new-age ice surface for which there is no friction between the ice and the hockey puck. You
BlackZzzverrR [31]

Answer:

<em>Not slow down or speed up</em>.

Explanation:

Hitting the puck accelerates the speed of the puck from zero to the speed with which it leaves at the instance they lose contact. Since there is no friction between the puck and the ice, there will be no force decelerating or accelerating the hockey puck, allowing the puck to move away and remain in motion without speeding up or slowing down indefinitely theoretically.

4 0
3 years ago
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