The amount of energy that was used to heat Cu is 27.6 cal
<u><em>calculation</em></u>
Heat (Q) = M ( mass) x c(specific heat capacity) x ΔT( change in temperature)
where;
Q=?
M = 5.0 g
C=0.092 cal/g°C
ΔT = 80°c-20°c=60°C
Q is therefore = 5.0 g x 0.092 cal / g°c x 60°c =27.6 cal
This is going to take a while..
1. 2AgI + Na2S --> Ag2S + 2NaI
2. Na3PO4 + 3HCl --> 3NaCl + N3PO4
3. Ba3N2 + 6H2O --> 3Ba(OH)2 + 2NH3
4. TiCl4 + 2H2O --> TiO2 + 4HCl
5. 3CaCl2 + 2Na3PO4 --> Ca3(PO4)2 + 6NaCl
6. 2NaBr + Cl2 --> 2NaCl + Br2
7. Mg(OH)2 + 2HCl --> MgCl2 + 2H2O
Hopefully that helps.
O = C = O Straight because there is no solitary electrons on C
