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3 years ago

15

Suppose that a dependent quantity increases when the independent quantity is decreased. This kind of proportional relationship b

etween the two quantities is called

1 answer:

Anna71 [15]3 years ago

3 0

I thinks it’s not this article we should cajnges it

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If you find that a substance turns litmus paper to blue and contains hydrogen ions it is most likely what

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An acid, possibly a strong one

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3 years ago

What Group is this atom located use a number only<br> *

Anastasy [175]

7 count the dots in the middle for you answer and if not it’s 3

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2 years ago

You are given two unknown acids, HX and H2Y, and two values for Ka, 1x10^-7 and 1x10^9. You know that X is a much more electrone

Elena L [17]

Answer:

.

Explanation

In HX , X is more electronegative than Y so HX will ionise more because of ionic bond between H and X . On the other hand H₂Y will be less polar as compared to HX so it will ionise to a lesser extent . Hence Ka will be more for HX . Ka represents the degree of ionisation of acid . Higher the ionisation , higher is the value of Ka . H₂Y which is less polar will ionise less and hence it will have lesser value of Ka .

Hence H₂Y will have value of 10⁻⁷ and HX will have value of ka equal to 10⁹ .

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3 years ago

Why is it that 85.48 rounded to two significant figures is 85 and not 86?

Gelneren [198K]

Answer:

See below.

Explanation:

That is because of the .48.

85.48 is closer to 85 than 86.

8 0

3 years ago

How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O)? For example if th

oee [108]

Given :

Mass of oxygen containing carbon monoxide (CO) is 2.666 gram .

To Find :

How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O) .

Solution :

By law of constant composition , a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation.

So , volume of solution does not matter .

Moles of oxygen , $n=\dfrac{2.666}{16}=0.167\ mole$ .

Now , molecule of CO contains 1 mole of C .

So , moles of C is also 0.167 mole .

Mass of carbon , $m=12\times 0.167=2\ g$ .

Therefore , mass of carbon is 2 grams .

Hence , this is the required solution .

5 0

3 years ago