Answer:
NaCl: ionic, HF: hydrogen bond, HCl: dipole dipole , F2: dispersion force
Explanation:
complete question is:
The four major attractive forces between particles are ionic bonds, dipole-dipole attractions, hydrogen bonds, and dispersion forces. Consider the compounds below, and classify each by its predominant attractive or intermolecular force among atoms or molecules of the same type.Identify each of the following ( NaCl, HF, HCl, F2) as Ionic, H Bonding, Dipole or Dispersion.
In an exothermic reaction, the water will increase in temperature in a calorimeter. An exothermic reaction is a reaction where heat is one of the products or heat is being released from it which will cause for the temperature inside the calorimeter to increase.
<span>Begin by classifying which energy level, and indirectly principal quantum number, n, resembles to the N shell.
no. of orbitals =n2
In your case, the fourth energy level will contain
n=4⇒no. of orbitals= 4^2=16
The number of subshells is given by the principal quantum number.
no. of subshells=n
In your case, the fourth energy level will have
no. of subshells = 4 this is the answer
to check:
the fourth energy shell will can hold a thoroughgoing of no. of electrons=2⋅42=32 e−</span>
A chemical property is a characteristic of a substance that may be observed when it participates in a chemical reaction. Examples of chemical properties include flammability, toxicity, chemical stability, and heat of combustion
Answer:
a) No. of moles of hydrogen needed = 5.4 mol
b) Grams of ammonia produced = 27.2 g
Explanation:
![N_2 (g) + 3H_2(g) \rightarrow 2NH_3 (g)](https://tex.z-dn.net/?f=N_2%20%28g%29%20%20%2B%20%203H_2%28g%29%20%5Crightarrow%202NH_3%20%28g%29)
a)
No. of moles of nitrogen = 1.80 mol
1 mole of nitrogen reacts with 3 moles of hydrogen
1.80 moles of nitrogen will react with
= 1.80 × 3 = 5.4 moles of hydrogen
b)
No. of moles of hydrogen = 2.4 mol
It is given that nitrogen is present in sufficient amount.
3 moles of hydrogen produce 2 moles of ![NH_3](https://tex.z-dn.net/?f=NH_3)
2.4 moles of hydrogen will produce
= ![\frac{2}{3} \times 2.4 = 1.6\ mol\ of\ NH_3](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D%20%5Ctimes%202.4%20%3D%201.6%5C%20mol%5C%20of%5C%20NH_3)
Molar mass of ammonia = 17 g/mol
Mass in gram = No. of moles × Molar mass
Mass of ammonia in g = 1.6 × 17
= 27.2 g