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ValentinkaMS [17]
3 years ago
8

Give the name and formula of the compound formed from the following elements: (a) sodium and nitrogen; (b) oxygen and strontium;

(c) aluminum and chlorine.
Chemistry
1 answer:
lisov135 [29]3 years ago
4 0

<u>Answer:</u>

<u>For a:</u> The chemical name and chemical formula formed is sodium nitride and Na_3N

<u>For b:</u> The chemical name and chemical formula formed is strontium oxide and SrO

<u>For c:</u> The chemical name and chemical formula formed is aluminium chloride and AlCl_3

<u>Explanation:</u>

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

The nomenclature of ionic compounds is given by:

1. Positive is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

  • <u>For a:</u> Sodium and nitrogen:

Sodium is the 11th element of periodic table having electronic configuration of [Ne]3s^1

To form Na^{+} ion, this element will loose 1 electron.

Nitrogen is the 7th element of periodic table having electronic configuration of [He]2s^22p^3.

To form N^{3-} ion, this element will gain 3 electrons.

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for sodium nitride is Na_3N

  • <u>For b:</u> Oxygen and strontium

Strontium is the 38th element of periodic table having electronic configuration of [Kr]5s^2.

To form Sr^{2+} ion, this element will loose 2 electrons.

Oxygen is the 8th element of periodic table having electronic configuration of [He]2s^22p^4.

To form O^{2-} ion, this element will gain 2 electrons.  

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for strontium oxide is SrO

  • <u>For c:</u> Aluminium and chlorine

Aluminium is the 13th element of periodic table having electronic configuration of [Ne]3s^23p^1

To form Al^{3+} ion, this element will loose 3 electrons.

Chlorine is the 17th element of the periodic table having electronic configuration of [Ne]3s^23p^5

To form Cl^{-} ion, this element will gain 1 electron.

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for aluminium chloride is AlCl_3

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Answer:

Percentage yield of carbon dioxide is 49.9%

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We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3(CH2)2CH3 + 13O2 —> 8CO2 + 10H2O

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2C4H10 + 13O2 —> 8CO2 + 10H2O

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Mass of C4H10 from the balanced equation = 2 × 58 = 116 g

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Mass of O2 from the balanced equation = 13 × 32 = 416 g

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Mass of CO2 from the balanced equation = 8 × 44 = 352 g

Summary:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen to produce 352 g of carbon dioxide.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen.

Therefore, 34.29 g of butane will react with = (34.29 × 416) / 116 = 122.97 g of oxygen.

From the calculation made above, we can see clearly that only 122.97 g out of 165.7 g of oxygen reacted completely with 34.29 g of butane. Therefore, butane is the limiting reactant and oxygen is the excess reactant.

Next, we shall determine the theoretical yield of carbon dioxide.

In this case, we shall use the limiting reactant because it will give the maximum yield of carbon dioxide as all of it is used up in the reaction.

The limiting reactant is butane and the theoretical yield of carbon dioxide can be obtained as follow:

From the balanced equation above,

116 g of butane reacted to produce 352 g of carbon dioxide.

Therefore, 34.29 g of butane will react to produce = (34.29 × 352) / 116 = 104.05 g of carbon dioxide.

Therefore, the theoretical yield of carbon dioxide is 104.05 g

Finally, we shall determine the percentage yield of carbon dioxide as follow:

Actual yield of carbon dioxide = 51.9 g

Theoretical yield of carbon dioxide = 104.05 g

Percentage yield of carbon dioxide =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield of carbon dioxide = 51.9 / 104.05 × 100

Percentage yield of carbon dioxide = 49.9%

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