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Shalnov [3]
2 years ago
10

What did Thomson’s model of the atom include that Dalton’s model did not have?

Chemistry
2 answers:
Allushta [10]2 years ago
6 0
Thomson's model included Protons and Electrons. His model is referred to as 'Plum Pudding' because of it.
Minchanka [31]2 years ago
5 0

Answer: subatomic particles: negative charges (electrons) distributed in a mass of positive charge.

Explanation:

1) John Dalton's model depicted the matter as the combination of tiny, indivisible particles, called atoms.

According to this model, atoms can not be created, destroyed, or divided into smaller particles.

2) When it was discovered that all forms of matter contained negative particles, by multiple experiments with cathode ray tubes, those particles where named electrons.

3) J.J. Thompson could determine that the mass of those negative charges was much smaller that the mass of the smallest atom (hydrogen). Concluding that existed smaller particles than the atom. Hence, Dalton's model was wrong: atoms was divisible into smaller subatomic particles.

4) Then J.J Thompson proposed the plum pudding model, in which the electrons (plums) are embeded into a uniform positive mass (pudding).

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Calculate the solubility of mn(oh)2 in grams per liter when buffered at ph=7.0. assume that buffer capacity is not exhausted
Vanyuwa [196]
When PH + POH = 14 
∴ POH = 14 -7 = 7

when POH = -㏒[OH-]

          7    = -㏒ [OH-]
∴[OH-] = 10^-7

by using ICE table:

           Mn(OH)2(s) ⇄  Mn2+ (aq)  + 2OH-(aq)
initial                              0                     10^-7
change                           +X                      +2X
Equ                                 X                  (10^-7 + 2X)

when Ksp = [Mn2+][OH-]^2

when Ksp of Mn(OH)2 = 4.6 x 10^-14

by substitution:

4.6 x 10^-14 = X*(10^-7+2X)^2  by solving this equation for X

∴ X =2.3 x 10-5 M

∴ The solubility of Mn(OH)2 in grams per liter (when the molar mass of Mn(OH)2 = 88.953 g/mol
= 2.3 x10^-5 moles/L * 88.953 g/mol

= 0.002 g/ L
3 0
3 years ago
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The answer is B

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