You have to find the stoichiometric ratio between AlCl₃ and BaCl₂. The common element between them is Cl. So, the ratio of Cl in BaCl₂ to AlCl₃ is 2/3. The molar mass of AlCl₃ is 133.34 g/mol. The solution is as follows:
Mass of AlCl₃ = (6 mol BaCl₂)(2 mol Cl/1 mol BaCl₂)(1 mol AlCl₃/3 mol Cl)(133.34 g/mol) = 533.36 g AlCl₃
Answer:
protons and neutrons
Explanation:
protons and neutrons is equal to mass number
4 m/s^2
I hope this helps!
Answer:
n = 2 mol
Explanation:
Given data:
Pressure = standard = 1 atm
Temperature = standard = 273.15 K
Volume = 44.8 L
Number of moles = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
1 atm × 44.8 L = n × 0.0821 atm.L/ mol.K × 273.15 K
44.8 atm.L = n × 22.43 atm.L/ mol
n = 44.8 atm.L / 22.43 atm.L/ mol
n = 2 mol
