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raketka [301]
3 years ago
5

Why are there 8 elements in the 3rd stage in a periodic table ?​

Chemistry
2 answers:
Olin [163]3 years ago
5 0

Answer:

stu pid

Explanation:

olga2289 [7]3 years ago
3 0

Answer:

PLEASE MARK ME AS THE BRAINLIEST

Explanation:

According to the 2n2 rule, the maximum number of electrons in the third period = 2 x (3)2 = 18. But, the last shell cannot accommodate more than 8 electrons so, the number of electrons in third period is 8. Hence, the number of elements is also 8.

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Assume that the pressure inside of the 1 liter balloon is 200,000 Pa, what is the explosive energy in the inside the balloon? Ex
AysviL [449]

Answer:

200 Joules is the explosive energy in the inside the balloon. And that is  9.523\times 10^{-5}1 lb of TNT.

Explanation:

Pressure=\frac{force}{Area}=\frac{Force\times distance}{Area \times distance}=\frac{Energy}{Volume}

Volume of the balloon = V = 1 L = 0.001 m^3

Pressure inside the balloon ,P= 200,000 Pa =200,000 N/m^2

Explosive energy in the inside the balloon be E.

E = Pressure × Volume

E=200,000 N/m^2\times 0.001 m^3=200 Joules

1 lb of TNT = 2.1\times 10^6 J

200 Joules = 200\times \frac{1}{2.1\times 10^6 }1 lb of TNT

= 9.523\times 10^{-5}1 lb of TNT

5 0
3 years ago
If 3.0 liters of oxygen gas react with excess carbon monoxide at STP, how many liters of carbon dioxide can be produced under th
mr_godi [17]

Answer:

The volume of CO2 produced is 6.0 L (option D)

Explanation:

Step 1: Data given

Volume of oxygen = 3.0 L

Carbon monoxide = CO = in excess

Step 2: The balanced equation

2 CO (g) + O2 (g) → 2 CO2 (g)

Step 3: Calculate moles of O2

1 mol of gas at STP = 22.4 L

3.0 L = 0.134 moles

Step 3: Calculate moles of CO2

For 2 moles CO we need 1 mol of O2 to produce 2 moles of CO2

For 0.134 moles O2 we'll have 2*0.134 = 0.268 moles CO2

Step 4: Calculate volume of CO2

1 mol = 22.4 L

0.268 mol = 22.4 * 0.268 = 6.0 L

The volume of CO2 produced is 6.0 L

8 0
3 years ago
I know I made a few errors but I don’t know which ones please help me
emmainna [20.7K]

Answer:

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7 0
3 years ago
How many liters of a 6.0 M solution of acetic acid contain 0.0030 moles​
fenix001 [56]

Answer: Least Common Multiplier of a6m, 0.003 moles 0.01elamos

Steps 6m, 0.003 moles

Compute an expression comprised of Factors that appear either in a6m or 0.003 moles

= 0.018elamos

Explanation:

5 0
3 years ago
Find the mass in grams of 2.00 x 10^23 molecules of C10 h15 09.( called penguinone because its structure looks like a penguin.)
Dafna1 [17]
2.00x10^23 x 1 mol/6.02x10^23 molecules x 279.25g C10H15O9/1 mol 
= 92.77 grams 
Molar mass of C10H15O9 is 279.25 grams. 

So the answer is 92.77 grams 
6 0
3 years ago
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