Two cyclist leaves town 200 mi apart at the same time and travel toward each other. One travels at 10mi/h slower than the other.
The they meet in 5 hours, what is the rate of each cyclist
1 answer:
Let x be the rate of speed of slower cyclist
and x+10 = rate of speed of faster cyclist
Distance = Speed * Time
5x + 5(x+10) = 200
5x + 5x + 50 = 200
10x = 200-50
10x = 150
x = 15
Rate of speed of slower cyclist: 15 mph
Rate of speed of faster cyclist = 15+10 => 25 mph
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