The vertical component of velocity is zero
It seems that you have missed the necessary options for us to answer this question so I had to look for it. But anyway, here is the answer. If Dr. John Sutherland is correct, the one that was necessary <span> for inert carbon atoms to become part of the chemistry of earth is CYANIDE. Hope this helps.</span>
Answer:
¹/3 C3H8(g) + ⁵/3 O2(g)
Explanation:
The coefficient before every molecule is representative of the number of moles. We can represent it in ration form so as to calculate the question;
C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l) means;
For every 1 mole of C₃H₈(g) and 5 moles of O₂(g) produces 3 moles of CO₂(g) and 4 moles of H₂O(l).
Therefore to produce 1.00 mole of CO₂(g);
We represent it in ratio;
C₃H₈(g) : CO₂(g)
1 : 3
For more on evaluating moles in chemical reactions check out;
brainly.com/question/13967925
brainly.com/question/13969737
CH4 Methane which is the prototypical organic molecule and the others are chemical not sure about water
Answer:
a. P=188mmHg
Explanation:
A gas undergoing a change of volume and pressure at constant temperature (and not changing the number of molecules), follows Boyle's Law: 
The units of these quantities can be any measure of pressure and volume, so long as long as the units are the same between beginning and ending conditions.
Substitute and solve:
![(685[mmHg])(131[mL])=P_2(478[mL])](https://tex.z-dn.net/?f=%28685%5BmmHg%5D%29%28131%5BmL%5D%29%3DP_2%28478%5BmL%5D%29)
![\dfrac{(685[mmHg])(131[mL\!\!\!\!\!\!\!\!\!{--}])}{478[mL\!\!\!\!\!\!\!\!\!{--}]}=\dfrac{P_2(478[mL]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}{478[mL] \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%28685%5BmmHg%5D%29%28131%5BmL%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%7B--%7D%5D%29%7D%7B478%5BmL%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%7B--%7D%5D%7D%3D%5Cdfrac%7BP_2%28478%5BmL%5D%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%7B----%7D%29%7D%7B478%5BmL%5D%20%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%5C%21%7B----%7D%7D)
![187.730125523[mmHg]=P_2](https://tex.z-dn.net/?f=187.730125523%5BmmHg%5D%3DP_2)
Accounting for significant figures, ![P_2=188[mmHg]](https://tex.z-dn.net/?f=P_2%3D188%5BmmHg%5D)
