The first dissociation for H2X:
H2X +H2O ↔ HX + H3O
initial 0.15 0 0
change -X +X +X
at equlibrium 0.15-X X X
because Ka1 is small we can assume neglect x in H2X concentration
Ka1 = [HX][H3O]/[H2X]
4.5x10^-6 =( X )(X) / (0.15)
X = √(4.5x10^-6*0.15)
∴X = 8.2 x 10-4 m
∴[HX] & [H3O] = 8.2x10^-4
the second dissociation of H2X
HX + H2O↔ X^2 + H3O
8.2x10^-4 Y 8.2x10^-4
Ka2 for Hx = 1.2x10^-11
Ka2 = [X2][H3O]/[HX]
1.2x10^-11= y (8.2x10^-4)*(8.2x10^-4)
∴y = 1.78x10^-5
∴[X^2] = 1.78x10^-5 m
It's an allele not a chromosome
The correct answer is letter a, whereas, carrying capacity
in captivity increases population size. It is because the carrying captivity is
the one responsible for having a maximum population size in which will help in
sustaining the necessities that the species need in the environment in which
makes it responsible for the population size to increase depending on its
capacity. The correct answer is letter a.
Answer:
B:the second answer
Explanation:
Because the all have leaves
Answer:
(iodine?) heptabromide
Explanation:
Not sure what element Ig is but use that name and then heptabromide.