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inessss [21]
3 years ago
12

Juan wants to dilute a 5 molar solution of sulfuric acid down to a 1 molar solution. What would be the best way for him to do th

is?
A.
Add 400 mL of water to a beaker filled with 100 mL of sulfuric acid.
B. Add 400 mL of a base such as NaOH to 100 mL of sulfuric acid.
C. Add 100 mL of sulfuric acid to 400 mL of a base such as NaOH.
D.
Add 100 mL of sulfuric acid to a beaker filled with 400 mL of water.
Physics
2 answers:
Sophie [7]3 years ago
8 0
Add 100 ML of sulfuric acid to 400 ML of base as an 80H B.
eduard3 years ago
6 0
The answer is D. Add 100 mL of sulfuric acid to a beaker filled with 400mL of water
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If a body with a mass of 4 kg is moved by a force of 20 N, what is the rate of its acceleration?​
valentina_108 [34]

Explanation:

F = ma

20 N = (4 kg) a

a = 5 m/s²

8 0
3 years ago
HELP ASAP PLZ
vredina [299]

Answer:

d

Explanation:

the atomic number and the mass number must not change. so you're just looking for the particle that makes the numbers on both sides the same

7 0
3 years ago
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A clarinet sounds as a closed pipe. if a clarinet sounds a note with a pitch of 375 hz, what are the frequencies of the lowest t
mote1985 [20]
So mathematical harmonics are based around a divergent set of fractions. Sigma(1/n)
with the 1st harmonic being... well 1, or 1 full wavelength.The second harmonic is exactly 1/2 the wavelength of the 1st with the third being 1/3 the wavelength. As Wavelengths go down, frequencies go up in a perfect ratio.

Second Harmonic has double the Frequency of the 1st or base note. Third Harmonic is triple and so on.

So the Harmonic set of 375 is.
1. 375
2. 375×2=750
3. 375×3= 1125
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.
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etc (: I hope this helps.
8 0
3 years ago
An object weighs 10N on earth .what is the objects weight on a planet one tenth the earths mass and one half its radius?
earnstyle [38]
We know, weight = mass * gravity 
10 = m * 9.8
m = 10/9.8 = 1.02 Kg

Now, Let, the gravity of that planet = g'
g' = m/r²   [m,r = mass & radius of that planet ]
g' = M/10 / (1/2R)²   [M, R = mass & radius of Earth ]
g' = 4M / 10R²
g' = 2/5 * M/R²
g' = 2/5 * g   
g' = 2/5 * 9.8
g' = 3.92

Weight on that planet = planet's gravity * mass
W' = 3.92 * 1.02
W' = 4 N

In short, Your Answer would be 4 Newtons

Hope this helps!
3 0
4 years ago
A jet is travelling at a speed of 1200 km/h and drops cargo from a height of 2.5 km above the ground Calculate the time it takes
OLEGan [10]

a) Time of flight: 22.6 s

To calculate the time it takes for the cargo to reach the ground, we just consider the vertical motion of the cargo.

The vertical position at time t is given by

y(t) = h +u_y t - \frac{1}{2}gt^2

where

h = 2.5 km = 2500 m is the initial height

u_y = 0 is the initial vertical velocity of the cargo

g = 9.8 m/s^2 is the acceleration of gravity

The cargo reaches the ground when

y(t) = 0

So substituting it into the equation and solving for t, we find the time of flight of the cargo:

0 = h - \frac{1}{2}gt^2\\t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(2500)}{9.8}}=22.6 s

b) 7.5 km

The range travelled by the cargo can be calculated by considering its horizontal motion only. In fact, the horizontal motion is a uniform motion, with constant velocity equal to the initial velocity of the jet:

v_x = 1200 km/h \cdot \frac{1000 m/km}{3600 s/h}=333.3 m/s

So the horizontal distance travelled is

d=v_x t

And if we substitute the time of flight,

t = 22.6 s

We find the range of the cargo:

d=(333.3)(22.6)=7533 m = 7.5 km

7 0
3 years ago
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