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-BARSIC- [3]
3 years ago
11

An unnamed professor is walking to class when an office chair (travelling in the same direction) collides with them. The profess

or fails into the chair and remains in the chair after collision. The professor, with a mass of 113kg, is travelling at 1.56 m/s. The chair has a velocity of 6.5 m/s, and a mass of 10kg. After the collision, and ignoring any effects of professor falling, what would be the speed of the chair professor system
Physics
1 answer:
ololo11 [35]3 years ago
5 0

Answer: 1.96 m/s

Explanation:

Given

Mass of Professor m_1=113\ kg

Velocity of professor u_1=1.56\ m/s

mass of chair m_2=10\ kg

velocity of chair u_2=6.5\ m/s

Suppose  after the collision, v is the common velocity

Conserving momentum

\Rightarrow m_1u_1+m_2u_2=(m_1+m_2)v\\\\\Rightarrow v=\dfrac{113\times 1.56+10\times 6.5}{113+10}=\dfrac{241.28}{123}\\\\\Rightarrow v=1.96\ m/s

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Two equivalent hybridized orbitals will form from the mixing of one s-orbital and one p-orbital, that is (sp) orbital.

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The orbitals that are formed by the mixing of these orbitals are called hybrid orbitals.

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2 years ago
A 3.00 kg mass is traveling at an initial speed of 25.0 m/s. What is the
Nitella [24]

Answer:

The magnitude of the force required to bring the mass to rest is 15 N.

Explanation:

Given;

mass, m = 3 .00 kg

initial speed of the mass, u = 25 m/s

distance traveled by the mass, d = 62.5 m

The acceleration of the mass is given as;

v² = u² + 2ad

at the maximum distance of 62.5 m, the final velocity of the mass = 0

0 = u² + 2ad

-2ad = u²

-a = u²/2d

-a = (25)² / (2 x 62.5)

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a = -5 m/s²

the magnitude of the acceleration = 5 m/s²

Apply Newton's second law of motion;

F = ma

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Therefore, the magnitude of the force required to bring the mass to rest is 15 N.

4 0
3 years ago
A bus moving along a level road increases its speed from 20 m/s to 35 m/s in 15.0s. What is the car's acceleration?​
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Explanation:

initial velocity U = 20m/s

Final velocity V = 35m/s

time = 15.0 secs

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acceleration a = change in velocity/time V/t

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Hence, your acceleration is 1m/s^2

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Answer:

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