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-BARSIC- [3]
2 years ago
11

An unnamed professor is walking to class when an office chair (travelling in the same direction) collides with them. The profess

or fails into the chair and remains in the chair after collision. The professor, with a mass of 113kg, is travelling at 1.56 m/s. The chair has a velocity of 6.5 m/s, and a mass of 10kg. After the collision, and ignoring any effects of professor falling, what would be the speed of the chair professor system
Physics
1 answer:
ololo11 [35]2 years ago
5 0

Answer: 1.96 m/s

Explanation:

Given

Mass of Professor m_1=113\ kg

Velocity of professor u_1=1.56\ m/s

mass of chair m_2=10\ kg

velocity of chair u_2=6.5\ m/s

Suppose  after the collision, v is the common velocity

Conserving momentum

\Rightarrow m_1u_1+m_2u_2=(m_1+m_2)v\\\\\Rightarrow v=\dfrac{113\times 1.56+10\times 6.5}{113+10}=\dfrac{241.28}{123}\\\\\Rightarrow v=1.96\ m/s

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A 4.00 kg ball is swung in a circle on the edge of a 1.50 m rope. The time it takes for the ball to complete one rotation is 3.4
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Answer:

The answer is below

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Hopes this helps!

P.S. I hope this is right. If not sorry in advance.
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