8. A point of Charge +3.0 X 10^-7 Coulomb is placed 2.0 X 10^-2 from a second
1 answer:
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Answer:
D) 25 m/s
Explanation:
In order to solve this problem we must use the following kinematics equation.
where:
Vf = final speed [m/s]
Vi = initial speed = 0
a = acceleration = 5[m/s^2]
t = time = 5[s]
After 5 seconds the acceleration is equal to 5 [m/s^2]
Now replacing the values in the equation:
Vf = 0 + (5*5)
Vf = 25[m/s]
Answer:
v = 1.30 m/s
Explanation:
given,
mass hung = 0.35 Kg
spring stretched when load is hanged (x)= 0.13 m
now,
weight of the mass attached = Kx
m g = k x
0.35 x 9.8 = k x 0.13
k = 26.38 N/m
now, using conservation of energy
v = 1.30 m/s