Answer:
a) p = m1 v1 + m2 v2
, b) dp / dt = m1 a1 + m2 a2
, c) It is equivalent to force
dp / dt = 0
Explanation:
In this problem we have two blocks and the system is formed by the two bodies.
Part A. Initially they ask us to find the moment of the whole system
p = m1 v1 + m2 v2
Part B.
Find the derivative
dp / dt = m1 dv1dt + m2 dv2 / dt
dp / dt = m1 a1 + m2 a2
Part C.
Let's analyze the dimensions
m a = [kg] [m / s2] = [N]
It is equivalent to force
Part d
Acceleration is due to a net force applied
Part e
The acceleration of block 1 is due to the force exerted by block 2 during the moment change
Part f
Force of block 1 on block 2
True f12 = m1a1 f21 = m2a2
Part g
By the law of action and reaction are equal magnitude F12 = f21
Part H
dp / dt = 0
Isolated system F12 = F21 and the masses are constant. The total moment is only redistributed
Speed = (distance covered) / (time to cover the distance)
Speed = (1,000 meters / 8.6 minutes) x (1 minute / 60 seconds) = 1.94 m/s
(rounded)
Yes, It does require some math skills.
Answer:
The strength of the magnetic field is 0.0842 mT
Explanation:
Given:
Velocity of rod

Length of rod
m
Induced emf across the rod
V
According to the faraday's law
We have a special case for moving rod in magnetic field.
Induced emf in moving rod is given by,

Where
strength of magnetic field


T
mT
Therefore, the strength of the magnetic field is 0.0842 mT