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faust18 [17]
3 years ago
7

Uranium has three common isotopes. If the abundance of 234U is 0.0054%, the abundance of 235U is 0.7204% and the abundance of 23

8U is 99.2742%, what is the average atomic mass of uranium?
Chemistry
1 answer:
OlgaM077 [116]3 years ago
7 0

Answer:

237.9 amu

Explanation:

Given data:

Abundance of U-234 = 0.0054 %

Abundance of  U-235 = 0.7204%

Abundance of  U-238 = 99.2742%

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass  / 100

Average atomic mass = (0.0054×234)+(0.7204×235) +(99.2742×238)  /100

Average atomic mass =  1.2636+ 169.294+ 23627.2596 / 100

Average atomic mass = 23797.8172/ 100

Average atomic mass = 237.9 amu.

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What volume (in L) of oxygen will be required to produce 77.4 L of water vapor in the reaction below?
Inga [223]

Answer:

90.3 L

Explanation:

Given data:

Volume of water produced = 77.4 L

Volume of oxygen required = ?

Solution:

Chemical equation:

2C₂H₆ + 7O₂  →  4CO₂ + 6H₂O

It is known that,

1 mole = 22.414 L

There are 7 moles of oxygen = 7×22.414 = 156.9 L

There are 6 moles of water = 6×22.414 = 134.5 L

Now we will compare:

                               H₂O           :              O₂    

                               134.5         :              156.9

                                 77.4         :             156.9/134.5×77.4 =90.3 L

So for the production of 77.4 L water 90.3 L oxygen is required.

8 0
3 years ago
If the molar absorptivity constant for the red dye solution is 5.56×104 M-1cm-1, calculate the molarity of the red dye solution
Shtirlitz [24]

Explanation:

a) Using Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

where,

A = absorbance of solution = 0.945

c = concentration of solution = ?

l = length of the cell = 1.20 cm

\epsilon = molar absorptivity of this solution =5.56\times 10^4 M^{-1} cm^{-1}

0.945=5.56\times 10^4 M^{-1} cm^{-1}\times 1.20 \times c

c=1.4163\times 10^{-5} M=14.16 \mu M

(1\mu M=10^{-6} M)

14.16 μM is the molarity of the red dye solution at the optimal wavelength 519nm and absorbance value 0.945.

b) c=1.4163\times 10^{-5} mol/L

1 L of solution contains 1.4163\times 10^{-5} moles of red dye.

Mass of 1.4163\times 10^{-5} moles of red dye:

1.4163\times 10^{-5}\times 879.86g/mol=0.01246 g

(w/v)\%=\frac{\text{Mass of solute (g)}}{\text{Volume of solvent (mL)}}\times 100

red(w/v)\%=\frac{0.01246 g}{1000 mL}\times 100=0.001246\%

c) In order to dilute red dye solution by 5 times, we will need to add 1 L of water to solution of given concentration.

Concentration of red dye solution = c=1.4163\times 10^{-5} M

Concentration of red solution after dilution = c'

c=c'\times 5

1.4163\times 10^{-5} M=c'\times 5

c'=2.83\times 10^{-6} M

The final concentration of the diluted solution is 2.83\times 10^{-6} M

8 0
3 years ago
Explain how you can convert from the number of representative particles of a substance to moles of that substance.
Scrat [10]

Answer:

  • the number of representative contain in 1 mol of a substance equals to 6.o2x10^23 particles.
8 0
3 years ago
What are three methods of measuring the volume of an object?
Anarel [89]
L×w×h=v
length times width times height equals volume
the order in which you multiply does not matter
5 0
3 years ago
Easy way to remember the difference between ionic and covalent bonds?
patriot [66]

Answer:

ionic bonding occurs between ions and covalent bonding occurs when atoms have electrons in common (they share).

5 0
2 years ago
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