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Inessa [10]
1 year ago
12

What is the volume of 6.40 grams of O₂ gas at STP?

Chemistry
1 answer:
gtnhenbr [62]1 year ago
7 0

The volume of 6.40 grams of O₂ gas at STP is 4.48L (option A). Details about volume can be found below.

<h3>How to calculate volume?</h3>

The volume of a gas can be calculated using the following formula:

p = m/v

Where;

  • p = density
  • m = mass
  • v = volume

According to this question, the mass of O₂ gas at STP is 6.40 grams. The density of the gas at STP is 1.43 g/L.

1.43g/L = 6.4g/V

Volume of O2 = 6.4 ÷ 1.43 = 4.48L

Therefore, the volume of 6.40 grams of O₂ gas at STP is 4.48L.

Learn more about volume at: brainly.com/question/1578538

#SPJ1

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Answer: The final pressure will decrease ad the value is 85 kPa

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

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We are given:

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8 0
3 years ago
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           Cp  =  Specific Heat Capacity  =  <u>??</u>

           ΔT  =  Change in Temperature  =  43.6 °C  -  22 °C  =  21.6 °C

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                                Cp  =  Q / m ΔT

Putting values,

                                Cp  =  640 J / (125 g × 21.6 °C)

                                Cp  =  0.237 J.g⁻¹.°C⁻¹

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