What is the volume of 6.40 grams of O₂ gas at STP?

Chemistry

1 answer:

gtnhenbr [62]1 year ago

7 0

The volume of 6.40 grams of O₂ gas at STP is 4.48L (option A). Details about volume can be found below.

<h3>How to calculate volume?</h3>

The volume of a gas can be calculated using the following formula:

p = m/v

Where;

p = density
m = mass
v = volume

According to this question, the mass of O₂ gas at STP is 6.40 grams. The density of the gas at STP is 1.43 g/L.

1.43g/L = 6.4g/V

Volume of O2 = 6.4 ÷ 1.43 = 4.48L

Therefore, the volume of 6.40 grams of O₂ gas at STP is 4.48L.

Learn more about volume at: brainly.com/question/1578538

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