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Inessa [10]
2 years ago
12

What is the volume of 6.40 grams of O₂ gas at STP?

Chemistry
1 answer:
gtnhenbr [62]2 years ago
7 0

The volume of 6.40 grams of O₂ gas at STP is 4.48L (option A). Details about volume can be found below.

<h3>How to calculate volume?</h3>

The volume of a gas can be calculated using the following formula:

p = m/v

Where;

  • p = density
  • m = mass
  • v = volume

According to this question, the mass of O₂ gas at STP is 6.40 grams. The density of the gas at STP is 1.43 g/L.

1.43g/L = 6.4g/V

Volume of O2 = 6.4 ÷ 1.43 = 4.48L

Therefore, the volume of 6.40 grams of O₂ gas at STP is 4.48L.

Learn more about volume at: brainly.com/question/1578538

#SPJ1

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Read 2 more answers
Calculate the molarity of 90.0 mL of a solution that is 0.92 % by mass NaCl. Assume the density of the solution is the same as p
jeka94
Answer is: molarity is 0,155 M.
V(solution) = 90,0 mL = 0,09 L.
ω(NaCl) = 0,92% ÷ 100% = 0,0092.
d(solution) = 1 g/mL.
m(solution) = V(solution) · d(solution).
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m(NaCl) = 90 g · 0,0092 = 0,828 g.
n(NaCl) = 0,828 g ÷ 58,4 g/mol.
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