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4 years ago

Which do you think changes the land more frozen water or flowing water?

Physics

2 answers:

Maksim231197 [3]4 years ago

8 0

I believe flowing water changes the land because eventually frozen water has to melt to flowing water, right?

Vsevolod [243]4 years ago

3 0

Flowing because frozen is solid & people wouldn't survive with out flowing water.

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Baseball scouts often use a radar gun to measure the speed of a pitch. One particular model of radar gun emits a microwave signa

Firdavs [7]

Since the Units presented are not in the International System we will proceed to convert them. We know that,

$1 mi/h = 0.447 m/s$

So the speed in SI would be

$V=95mi/h(\frac{0.447m/s}{1mi/h})$

$V=42.465 m/s$

The change in frequency when the wave is reflected is

$f'=f(1+\frac{V}{c})$

Or we can rearrange the equation as

$f' = f + f\frac{V}{c}$

f' = Apparent frequency

f = Original Frequency

c = Speed of light

$f'-f = f\frac{V}{c}$

$\Delta f = f\frac{V}{c}$

Replacing,

$\Delta f = (10.525*10^9)(\frac{42.465}{3*10^8})$

$\Delta f =1489.8 Hz$

Since the waves are reflected, hence the change in frequency at the gun is equal to twice the change in frequency

$\Delta f_T = 2 \Delta f$

$\Delta f_T = 2(1489.8Hz)$

$\Delta f_T = 2979.63Hz$

Therefore the increase in frequency is 2979.63Hz

4 0

4 years ago

A train is traveling at a speed of 50km/hr. How.many hours will it take the train to travel 800 km?

bagirrra123 [75]

Answer:

It would take 16 hours

Explanation:

800 divided by 50 = 16

Brainly pls

8 0

3 years ago

Read 2 more answers

The solar constant is a. the same for a sphere or for a circle. b. only about a quarter of all energy emitted by the sun. c. a c

kvasek [131]

Answer:

Explanation:

5 0

3 years ago

Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approxim

sergiy2304 [10]

Answer:

10.53m/s²

Explanation:

Centripetal acceleration is the acceleration of an object about a circle. The formula for calculating centripetal acceleration is expressed by:

$a = \frac{v^2}{r}$

v is the velocity of the car = 24.5m/s

r is the radius of the track = 57.0m

Substitute the given values into the formula:

$a = \frac{24.5^2}{57} \\\\a = \frac{600.25}{57}\\ \\a = 10.53m/s^{2}$

Hence the centripetal acceleration of the race car is 10.53m/s²

6 0

3 years ago

A golfer, driving a golf ball off the tee, gives the ball a velocity of 38 m/sec. The mass of the ball is 0.045 kg, and the dura

atroni [7]

Answer:

$\Delta p=1.71\frac{kg\cdot m}{s}$

Explanation:

The momentum of a body is defined as the product of its mass and its velocity at a given time. Therefore the change in the momentum of the ball is given by the difference between the final momentum and the initial momentum:

$\Delta p=p_f-p_i\\\Delta p=mv_f-mv_i\\\Delta p=m(v_f-v_i)\\\Delta p=0.045kg(38\frac{m}{s}-0\frac{m}{s})\\\Delta p=1.71\frac{kg\cdot m}{s}$

6 0

4 years ago