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aleksley [76]
3 years ago
12

The sum of the kinetic and potential energies of a system of objects is conserved: Group of answer choices only when no external

force acts on the objects only when the objects move along closed paths only when the work done by the resultant external force is zero none of the above
Physics
1 answer:
uysha [10]3 years ago
7 0

The sum of the kinetic and potential energies of a system of objects is conserved only when no external force acts on the objects.

<h3>Conservation of mechanical energy</h3>

The principle of conservation of mechanical energy states that the total mechanical energy of an isolated system (absence of external force) is always constant.

M.A = P.E + K.E

where;

P.E is potential energy

K.E is kinetic energy

Thus, the sum of the kinetic and potential energies of a system of objects is conserved only when no external force acts on the objects.

Learn more about conservation of mechanical energy here: brainly.com/question/24443465

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A Carnot engine has an efficiency of 0.537, and the temperature of its cold reservoir is 379 K.
katen-ka-za [31]

Answer:

(A) Th = 818.6 K

(B) Qh = 14211.7 J

Explanation:

efficiency (n) = 0.537

temperature of cold reservoir (Tc) = 379 K

heat rejected (Qc) = 6580 J

(A) find the temperature of the hot reservoir (Th)

 n = 1 - \frac{Tc}{Th}

0.537 = 1 - \frac{379}{Th}

\frac{379}{Th} = 1 - 0.537 = 0.463        

Th = \frac{379}{0.463}

Th = 818.6 K

(B) what amount of heat is put into the engine (Qh) ?

from \frac{Tc}{Th} = \frac{Qc}{Qh}

Qh = 6580 ÷ \frac{379}{818.6}

Qh = 14211.7 J

8 0
3 years ago
The engine that moves the cables for the San Francisco cable cars delivers 390.3 kW of power for each line. How long does it tak
Musya8 [376]

Answer:

It would take 16.7 s for the work to be done by the engine.

Explanation:

From the question, given: Power = 390.3 kW

                                           Work to be done = 6.5 x 10^{6} J

But, power and work done with respect to time, has a relationship of:

Power = \frac{work done}{time}

So that,

time = \frac{work done}{Power}

Thus,

time  = \frac{6.5*10^{6} }{390.3*10^{3} }

       = 16.6539

time = 16.7 s

Time required is 16.7 seconds.

Thus, it would take 16.7 s for the work to be done by the engine.

5 0
3 years ago
Help meeeeeeeeeeee<br>what is the rheostat and what its ruleeee??​
andre [41]

Answer:

<h2><u>Rheostat:</u></h2>

=> Rheostat is an electric device used as a variable resistance, like the regulator of the fan. It is used to change the electric resistance in the electric circuit.

<h2><u>Principle / Rule:</u></h2>

=> Rheostat works on the principle of Ohm’s law. Ohm’s law states that current in a circuit is inversely proportional to the resistance at the given temperature.

\infty  \infty  \infty

8 0
3 years ago
Pick the right statement about normal force: (section 5.7)
Montano1993 [528]

Answer:

A. Normal force is always perpendicular to the area of contact between an object and support.

Explanation:

Normal force is defined as the contact force. If there is no contact between the surfaces, they cannot applies a force which is normal on each other. For e.g, the surfaces of a cubical box and the cart cannot applies a force of normal on each other because of no contact.

If, when there is a contact between two surfaces they applies a normal force on each other, and this force is  perpendicular to the each other . This normal force is necessary to prevent object to penetrating into other.

7 0
3 years ago
A motorist drives north for 36.0 minutes at 96.0 km/h and then stops for 15.0 minutes. He then continues north, traveling 130 km
Over [174]

Answer:

a) d=187.6km

b)v=61.5km/h

Explanation:

First we convert our minutes to hours so we work always in the same units.

36min=36min(\frac{1h}{60min})=0.6h

15min=15min(\frac{1h}{60min})=0.25h

Where we used the fact that 1 hour are 60 min, thus the multiplying factor is equal to 1 (not altering the time, just changing the units).

a) On the first part the motorist travels a distance d_1=v_1t_1=(96km/h)(0.6h)=57.6km, and on the second part he travels d_2=130km.

The total displacement is d=d_1+d_2=57.6km+130km=187.6km

b) The average velocity is the relation between the total displacement and the time taken to cover it. Our total time is t=0.6h+0.25h+2.2h=3.05h, thus we have:

v=\frac{187.6km}{3.05h}=61.5km/h

8 0
3 years ago
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