Answer:
a) R(fw) = 46.75*10⁶ (N)
b) R(rwi) = 70.125*10⁶ [N]
Explanation: See Attached file (the rectangle stands for a jet)
The diagram shows forces acting on the jet
Let R(fw) Reaction of front wheels and
R(rw) Reaction of rear wheels
Now we apply the Stevin relation, for R(fw) and a jet weight as follows
R(fw)/ 4 = 187*10⁶ / 16
Then :
R(fw) = ( 1/4) *187*10⁶ ⇒ R(fw) = 46.75*10⁶ (N)
And e do the same for the reaction on rear wheels
R(rw) / 12 = 187*10⁶ /16 ⇒ R(rw) =(3/4)*187*10⁶
R(rw) = 140,25*10⁶ [N]
The last expression is for the whole reaction, and must be devide by 2
because that force is exerted for two wheels, therefore on each of the two rear wheels the reaction will be:
R(rwi) = 70.125*10⁶ [N]
Answer:
Elastic potential energy into kinetic energy
Explanation:
Initially the energy is stored inside the spring, which is compressed. This form of energy is called elastic potential energy, and its formula is
where k is the spring constant, which gives the 'strength' of the spring, while x is the compression/stretching of the spring with respect to its equilibrium position.
When the spring unwinds, it returns to its equilibrium position, so x becomes zero and the potential energy converts into another form of energy, which is related to the motion of the car (in fact, the car starts moving). This form of energy is called kinetic energy, and its formula is
where m is the mass of the car and v is its speed.
Answer:
Explanation:
q1 = q2 = e = 1.6 x 10^-19 C
d = 2.7 x 10^-15 m
1. Work done is equal to the potential energy stored between the two charges.
The formula for the potential energy is given by
By substituting the values
U = 8.53 x 10^-14 J
So, the work done is 8.53 x 10^-14 J.
(2) d = 2 x 2.7 x 10^-15 m = 5.4 x 10^-15 m
So, the potential energy is
By substituting the values
U = 4.27 x 10^-14 J
(3) mass, m = 1 u = 1.67 x 10^-27 kg
So, the kinetic energy is equal to the potential energy.
Let v be the velocity.
v = 7.14 x 10^6 m/s
The formula is=1/2(m x v^2)
so = 1/2*(0.05)*(310)^2
ans is =2402.5 joules