(a) The LFL for n-hexane is
(b) of n-hexane is required to produce its own flammable mixture in of air.
Further explanation:
Stoichiometry of a reaction is used to determine the amount of species present in reaction by the relationship between reactants and products. It is used to determine moles of a chemical species when moles of other chemical species present in reaction is given.
Consider the general reaction,
Here,
A and B are reactants.
C is the product.
One mole of A reacts with two moles of B to produce three moles of C. The stoichiometric ratio between A and B is 1:2, the stoichiometric ratio between A and C is 1:3, and the stoichiometric ratio between B and C is 2:3.
Combustion reactions:
These are the reactions that take place when hydrocarbons are burnt in the presence of oxygen to form carbon dioxide and water. These are also referred to as burning.
Example of combustion reactions are as follows:
(a)
(b)
Lower Flammability Limit:
It is the minimum volume % of vapor that produces a combustible mixture. It is usually half the stoichiometric mixture concentration that is required for complete combustion of vapor in the air. It is written as LFL.
(a) The balanced chemical equation for combustion of n-hexane is as follows:
From the balanced chemical reaction, the reaction stoichiometry between and is as follows:
Consider 100 moles of air. The moles of oxygen can be calculated as follows;
…… (1)
The volume % of is 20.9 %.
The moles of air are 100 mol.
Substitute these values in equation (1).
19 moles of require 2 moles of n-hexane. So the amount of n-hexane required for 20.9 moles of is calculated as follows:
The formula to calculate LFL for n-hexane is calculated as follows:
…… (2)
Substitute 2.2 mol for the stoichiometric amount of in equation (2).
So LFL for n-hexane is 1.1 %.
(b) The LFL value for calculated in part (a) is used to find its volume. This is done by using equation (3).
The formula to calculate the volume of is as follows:
…… (3)
The LFL for is 1.1 %.
The volume of air is .
Substitute these values in equation (3).
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Mole concept
Keywords: stoichiometry, reactant, product, combustion, n-hexane, H2O, CO2, C6H14, LFL, stoichiometric amount, 1.1 %, 20.9 %, 20.9 mol, air, O2.