Question

Please help break down the following question in a step by step easy to comprehend process.

Answer 1

Answer:

The atomic mass of  iodine-131 is 130.9056485 amu.

Explanation:

Beta-decay is the process in which a neutron gets converted into a proton and an electron releasing a beta-particle. The beta particle released carries a charge of -1 units.

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

$_{53}^{131}\textrm{I}\rightarrow _{54}^{131}\textrm{Xe}+_{-1}^0\beta$

Energy released during beta particle emission = E

$E=\Delta mc^2$

$1.5541\times 10^{-33} J=\Delta m(3\times 10^8 m/s)^2$

$\Delta m=1.7267\times 10^{-50} kg$

$\Delta m=1.0399\times 10^{-23} amu$

Mass of reactant = Mass of product + Δm

=  Mass of beta particle + nuclide + Δm

Mass Beta-particle =$9.10938291\times 10^{-31} kg=0.000548579 amu$

Mass of reactant =

=130.9051+0.000548579 amu +$1.0399\times 10^{-23}$ amu

= 130.9056485 amu

The atomic mass of  iodine-131 is 130.9056485 amu.