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ser-zykov [4K]
3 years ago
13

The following lots of a particular commodity were available for sale during the year:Beginning inventory 10 units at $60First pu

rchase 25 units at $65Second purchase 30 units at $68Third purchase 15 units at $75The firm uses the periodic system and there are 25 units of the commodity on hand at the end of the year.What is the amount of the inventory at the end of the year using the average cost method?$1,685$1,575$1,805$3,705
Business
1 answer:
krok68 [10]3 years ago
3 0

Answer:

$1,685

Explanation:

The computation of the average cost per unit is shown below:

= (Beginning inventory units × price per unit + purchase inventory units × price per unit + purchase inventory units × price per unit + purchase inventory units × price per unit ) ÷ (Beginning inventory units + purchase inventory units + purchase inventory units + purchase inventory units )

= (10 units × $60 + 25 units × $65 + 30 units × $68 + 15 units × $75) ÷ (10 units + 25 units + 30 units + 15 units)

= ($600 + $1,625 + $2,040 + $1,125   ) ÷ (80 units)

= ($5,390 units) ÷ (80 units)

= $67.375 per unit

Now the ending inventory equals to

= Ending inventory units × average cost per unit)

=  25 units × $67.375 per unit

= $1,685

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3 years ago
Is coke and pepsi a duopoly
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Explanation:

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1 year ago
When an investigation shows that ill people have something in common to explain why they all got the same illness, the group of
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Answer:

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3 years ago
Jacob needed money for some unexpected expenses, so he borrowed $5,890.25 from a friend and agreed to repay the loan in seven eq
Anna11 [10]

Answer:

OPTION C i.e 11%

Option A i.e 30.55 year

Explanation:

we know that capital can be calculated as

Capital = EMI \times PVIFA

capital = EMI \times \frac{(1+r))^n -1}{r (1+r)^n}

from the data given in question we can calculate the value of r

so

5890.2 = 1250 \times \frac{(1+r))^7 -1}{r (1+r)^7}

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solving for r we get

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option C

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Total\ saving  =  cash flow \times FVIFA

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\frac{8452622}{40000}\times 0.11 = (1.11)^n -1

solving for n we get

n = 30.55 year.

Option A

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