Answer:
D. 100 J
Explanation:
Given
Mass (m) = 2 kg
Height (h) = 5 m
Acceleration due to gravity (g) = 10 m/s²
Now
Work done(W)
= m * g * h
= 2 * 10 * 5
= 100 Joule
Hope it will help :)❤
Answer:
Explanation:
acceleration is the time rate of change of velocity
a = (51 - 20) / 3 = 10⅓ mi/hr/s
which should probably be converted to standard units.
10⅓ mi/hr/s(5280 ft/mi) / 3600 s/hr) = 15.15555... ≈ 15.2 ft/s²
which is roughly half the acceleration of gravity.
<span>0.166666666667
Hope this helped!
STSN</span>
Before we could discuss this in any specific detail, I think we would have to
know the angles. A generic discussion without actual numbers for the angles
would be just plain too confusing.
The general approach is that the vertical components of both tensions
add up to 20N, and the horizontal components are equal but in opposite
directions. That's the only way that the mass is hanging motionless.
You have to find the horizontal and vertical components of the tensions
by using the angles and maybe the lengths of the ropes.
Answer:

Explanation:
The torque is the force by the distance so to determinate that both torque are the same magnitude so




Solve to d2

