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vovangra [49]
3 years ago
12

Consider two identical springs. At the start of an experiment, Spring A is already stretched out 3 cm, while Spring B remains at

the zero position. Both springs are then stretched an additional three centimeters. What conclusion can you draw about the force required to stretch these springs during the experiment
Physics
1 answer:
aksik [14]3 years ago
7 0

Answer:

Explanation:

In this interesting exercise we have that spring A is 3 cm longer, due to previous experiments if these experiments did not reach the non-linear elongation point, the cosecant Km of the spring must remain the same, therefore when we lengthen the two springs these the longitudinal are lengthened.

As a consequence of the above according to Hockey law, the prediction of lengthening is the same, therefore the outside is the same in two two systems

            F = K Δx

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Answer:

E(r) = λ/2πrε0

Explanation:

If we consider an infinitely long line of charge with the charge per unit length being λ, we can take advantage of the cylindrical symmetry of this situation.

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Niw, let's use a cylinder (with an arbitrary radius (r) and length (l)) centred on the line of charge as our Gaussian surface.

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Now, we know that according to Gauss Law,

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Thus,

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Since we are dealing with the radial component, the curved surface would be equidistant from the line of charge and the electric field in the surface will be the same magnitude throughout.

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E•2πrl = λl/ε0

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