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vovangra [49]
3 years ago
12

Consider two identical springs. At the start of an experiment, Spring A is already stretched out 3 cm, while Spring B remains at

the zero position. Both springs are then stretched an additional three centimeters. What conclusion can you draw about the force required to stretch these springs during the experiment
Physics
1 answer:
aksik [14]3 years ago
7 0

Answer:

Explanation:

In this interesting exercise we have that spring A is 3 cm longer, due to previous experiments if these experiments did not reach the non-linear elongation point, the cosecant Km of the spring must remain the same, therefore when we lengthen the two springs these the longitudinal are lengthened.

As a consequence of the above according to Hockey law, the prediction of lengthening is the same, therefore the outside is the same in two two systems

            F = K Δx

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A particle is moving with velocity v(t) = t2 _ 9t + 18 with distance, s measured in meters, left or right of zero, and t measure
Alex787 [66]
V = t^2 - 9t + 18

position, s
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Average velocity: distance / time

   distance: t = 8 => s = 8^3 / 3 - 4.5 (8)^2 + 18(8) + 1 = 27.67 m
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t = 5 s

     v = t^2 - 9t + 18 = 5^2 - 9(5) + 18 = -2 m/s
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Moving right
     V > 0 => t^2 - 9t + 18 > 0
     (t - 6)(t - 3) > 0

     => t > 6 and t > 3 => t > 6 s => Interval (6,8)

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Going faster and slowing dowm

acceleration, a = v' = 2t - 9
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4 0
3 years ago
The igneous rocks which were deposited on the surface and then cooled are known as __________.
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.A particle starts on the origin. It is pushed back to -5.7 m in 2.1 s. Then it is pushed
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The average velocity the add the velocities and divide them by 2.

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