Answer:
volume of the bubble just before it reaches the surface is 5.71 cm³ 
Explanation:
given data 
depth h = 36 m
volume v2 = 1.22 cm³ = 1.22 ×  m³
 m³
temperature bottom t2 = 5.9°C = 278.9 K
temperature top  t1 = 16.0°C = 289 K
to find out
what is the volume of the bubble just before it reaches the surface
solution
we know at top atmospheric pressure is about P1 =  Pa
 Pa
so pressure at bottom P2 = pressure at top + ρ×g×h
here ρ is density and h is height and g is 9.8 m/s²
so 
pressure at bottom P2 =  + 1000 × 9.8 ×36
 + 1000 × 9.8 ×36
pressure at bottom P2 =4.52 ×  Pa
  Pa
so from gas law 

here p is pressure and v is volume and t is temperature 
so put here value and find v1

V1 = 5.71 cm³ 
volume of the bubble just before it reaches the surface is 5.71 cm³ 
 
        
             
        
        
        
The Volume of the ice block is 5376.344 cm^3.
The density of a material is define as the mass per unit volume.
Here, the density of ice given is 0.93 g/cm^3
Mass of the ice block  given is 5 kg or 5000 g
Now calculate the volume of the ice block
density=mass/volume
0.93=5000/Volume
Volume =5376.344 cm^3
Therefore the volume of  ice block is 5376.344 cm^3
 
        
             
        
        
        
Answer:
A
Explanation:
I’m not sure but I hope this helped
 
        
             
        
        
        
Answer:
F = (913.14 , 274.87 )
|F| = 953.61 direction 16.71°
Explanation:
To calculate the resultant force you take into account both x and y component of the implied forces:

Thus, the net force over the body is:

Next, you calculate the magnitude of the force:

and the direction is:

 
        
             
        
        
        
Answer:
a)
b)
Explanation:
Given:
mass of bullet, 
compression of the spring, 
force required for the given compression, 
(a)
We know
 
where:
a= acceleration


we have:
initial velocity,
Using the eq. of motion:

where: 
v= final velocity after the separation of spring with the bullet. 


(b)
Now, in vertical direction we take the above velocity as the initial velocity "u"
so,

∵At maximum height the final velocity will be zero

Using the equation of motion:

where:
h= height
g= acceleration due to gravity


is the height from the release position of the spring.
So, the height from the latched position be:


