Answer:
The distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.
Explanation:
Given;
speed of the faster car, v₁ = 60 mi/h
speed of the slower car, v₂ = 55 mi/h
Let the distance traveled by the faster car when it is 15 mins ahead of the slower car = x miles

Note: divide 15 mins by 60 to convert to hours for consistency in the units.

Therefore, the distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.
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The net force required to accelerate a car is 6000 N.
Force is defined as the product of the mass and acceleration of the body. Force is used to changing the velocity that is to accelerate an object or a body of a particular mass. The unit of Force is Newton or kg m/s^2.
The formula used to calculate the net force is :
F = ma
where, F = Force
m = mass = 2000 kg
a = acceleration = 3.00 m/s^2
∴ F = 2000*3
F = 6000 N
Thus, to accelerate the car at 3.00 m/s^2 of mass 2000 kg net force required is 6000 N.
To learn more about force,
brainly.com/question/1046166
Answer:
Explanation:
the light ray leaving a medium in contrast to the entering or incident ray.