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Katyanochek1 [597]
3 years ago
5

What's the possible impact of the fees must fall?

Physics
1 answer:
garri49 [273]3 years ago
5 0
This is a complicated question. Please be more specific.

Thank You
You might be interested in
What are the two factors that affect the frictional force between two surfaces​
Talja [164]

Static friction and normal force? I would Google to double check if I'm right.

6 0
3 years ago
A car traveling at a velocity of 40 m/s accelerates at 5 m/s/s for 10 seconds. What is the car's final velocity?
Papessa [141]

Answer:

<h3>The answer is 90 m/s</h3>

Explanation:

To find the final velocity of an object given it's initial velocity , time taken and it's acceleration we use the formula

<h3>v = u + at </h3>

where

v is the final velocity

u is the initial velocity

t is the time taken

a is the acceleration

From the question

u = 40 m/s

t = 10s

a = 5 m/s²

We have

v = 40 + 5(10) = 40 + 50

We have the final answer as

<h3>90 m/s</h3>

Hope this helps you

8 0
3 years ago
HELP WITH THESE! IVE ASKED 5 TIMES!
Sedbober [7]

3). Acceleration = (change in speed) / (time for the change)

Why, that's just the slope of the speed graph. Looks like about 0.6 m/s² to me.

5). As I heard someone say just a moment ago: "Acceleration is just the slope of the speed graph". The slope of the graph in #5 is negative, and it's constant. So the acceleration is negative and constant.

4). The instantaneous accelerating at any point on this graph is the slope of the graph AT THAT POINT. It changes at different places on this graph, BUT, by the time it gets to 10 sec, the graph is pretty much a straight line, so you can get pretty close to estimating its slope right there in that small region. From 10-11 sec, I see the speed rise from 14 to 16 m/s, so the acceleration in that little area is 2 m/s² .

7). The speed is decreasing as time goes on, so the acceleration is negative. The graph has different slope in different places, so the acceleration is changing.

9). The speed is increasing as time goes on, so the acceleration is positive. The graph has different slope in different places, so the acceleration is changing.

last problem, no number). They want you to find a place on the speed graph where the acceleration is negative. That means a place where the speed is decreasing, so it has to be somewhere before 4 seconds ... after 4 seconds, the speed starts to increase as time goes on.

So now you just have to find a place on the graph, before 4 seconds, where the speed drops by 2 in the time of one second. I couldn't blow it up enough to work with it. It looks to me like it's about 1.5 seconds, but you'll have to check it out.

The reason I'm guessing 1.5 seconds:

-- at 1.5 sec, the speed is 3 m/s

-- 1/2 sec earlier, at 1.0 sec, the speed is 4 m/s

-- 1/2 sec later, at 2.0 sec, the speed is 2 m/s

So around 1.5 sec, you can see a place on the graph that's almost straight, and the speed decreases by 2 m/s in the space of 1 second. So the average acceleration from 1s to 2s is 2 m/s², and 1.5s is right in the middle of that period of time.

Oh phoo ! I didn't even look at the choices until just now and 1.5s isn't one of them. You ought to be able to handle them now. Remember, it has to be before 4 seconds, because the acceleration is all positive after that.

(I know this is more detailed than your class is expecting, and that's why my answer isn't one of the choices. There's a simple reason for my getting too complicated. You see, I've sweated through so many years of Calculus and Differential Equations that my brain got fried, and now, when I work on middle-school and high-school problems, it HAS TO go through those channels in my brain. There's no other way.)

7 0
3 years ago
During a workout, a football player pushes a blocking dummy a distance of 30 m. While pushing the dummy the same distance a seco
Pavel [41]

Explanation:

Power = work / time

Work = force × distance

Therefore:

Power = force × distance / time

Since the distance is the same, he would have to either increase the force he exerts or decrease the time (increase his velocity) in order to increase the amount of work done.

5 0
3 years ago
A small 22 kilogram canoe is floating downriver at a speed of 3 m/s. What is the canoe's kinetic energy?
amid [387]
Kinetic energy can be calculated using the following rule:
kinetic energy = 0.5*m*v^2 where:
m is the mass = 22 kg
v is the velocity = 3 m/sec

Substitute with the givens in the above equation to get the kinetic energy as follows:
kinetic energy = 0.5(22)(3)^2
kinetic energy = 99 Joules
4 0
3 years ago
Read 2 more answers
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