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WINSTONCH [101]
3 years ago
13

If a right angle is bisected what type of angles are formed

Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

If a right angle is bisected, <em>complementary angles</em> are formed. Complementary Angles are angles that <u>add up to 90°, which is also known as the right angle.</u>

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1/4y =6
kondaur [170]

Answer: Y=24

Step-by-step explanation:1/4 y=6  

                                              *4     *4

                                               y= 24

Math really is a universal language, Buenos noches amigo.

5 0
3 years ago
For the function f(x) = x^2+ 3, what are the outputs for the inputs -3, 2, 0, and 5?
AysviL [449]

Answer:

F(-3)=12

F(2)=7

F(0)=3

F(5)=28

Step-by-step explanation:

8 0
3 years ago
Jack spends 1 1/2 as long on his homework as Jill. Last week Jill spent 9 1/2 hours doing homework. How long did Jack spend doin
alina1380 [7]
The amount of time Jill spent to do her homework 
= 9 1/2 hours. which equals to  570 minutes.

Which means, the amount of times Jack needed to do his is 
= 570 minutes x 1.5
= 855 minutes which equals to 14 1/4 hours

hope this helps
7 0
3 years ago
A: What are the solutions to the quadratic equation x2+9=0? B: What is the factored form of the quadratic expression x2+9? Selec
Paraphin [41]

Answer:

A. The solutions are x=3i,\:x=-3i.

B. The factored form of the quadratic expression x^2+9=(x-3i)(x+3i)

Step-by-step explanation:

A. To find the solutions to the quadratic equation x^2+9=0 you must:

\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}

x=\sqrt{-9} = \sqrt{-1}\sqrt{9}=\sqrt{9}i=3i\\\\x=-\sqrt{-9}=-\sqrt{-1}\sqrt{9}=-\sqrt{9}i=-3i

The solutions are:

x=3i,\:x=-3i

B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.

To factor x^2+9:

First, multiply the constant in the polynomial by i^2 where i^2 is equal to -1.

x^2+9i^2

Since both terms are perfect squares, factor using the difference of squares formula

a^2-i^2=(a+i)(a-i)

x^2+9=x^2+9i^2=\left(-3i+x\right)\left(3i+x\right)

5 0
3 years ago
Pleaseeeeeeee friends
IgorC [24]
B(x)=x2+3
I believe so
3 0
3 years ago
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