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denis-greek [22]
3 years ago
5

The second step in solving problems using order of operations is solving the

Mathematics
2 answers:
inna [77]3 years ago
6 0
PEMDAS.....parenthesis, exponents, multiplication/division, addition/subtraction

so step 2 is solving the exponents <==
Sav [38]3 years ago
6 0

Answer: Exponents

Explanation: To summarize, use the following order of operations to simplify.

Parentheses, then exponents, then multiplication/division, then addition and subtraction.

Exponents will always come second unless you have parentheses.

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I need help plzz <br> it do to day
eduard

Answer:

-8x+c

Step-by-step explanation:

c-8x

= -8x+c

\:

8 0
2 years ago
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Cat food costs $2.85 for five cans. Ben only wants to buy one can. How much will it cost?
sergejj [24]

Answer:

$0.57 for each can of cat food

Step-by-step explanation:

2.85/5 = 0.57 giving you the answer

7 0
2 years ago
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A triangle weighs 3 grams and a circle weighs 6 grams. Find the weight of a square in Hanger A and the weight of a pentagon in H
Zanzabum

Answer:

Equation of Hanger A:

x + y = z

z = 9 grams

Equation for hanger B

x + y = p

p = 9 grams

Step-by-step explanation:

Note: This question is not complete, and lacks necessary data to answer this question. But for the sack of concept, we wil be solving this question using our own data.

Data given:

Triangle weight = 3 grams

Circle weight = 6 grams

There are two hangers A and B.

We have to find weight of the square in Hanger A and weight of the pentagon in Hanger B.

So, for your understanding I have drawn the two hangers A and B. In A we have triangle and circle on the LHS and the square on the right. On the other hand, we have pentagon on the right and triangle and circle.

Sketch is attached in the attachment.

Let's suppose: Hanger A is balanced, So,

Triangle weight = 3 grams = x

Circle weight = 6 grams = y

weight of the pentagon in Hanger B = p

weight of the square in Hanger A = z =?

So,

Equation of Hanger A:

x + y = z

z = 3 + 6

z = 9 grams  = weight of the square in Hanger A

Similarly for Hanger B.

Equation for hanger B

x + y = p

p = 3 + 6

p = 9 grams

6 0
2 years ago
Lines sand tare perpendicular. If the slope of line sis 5, what is the slope of<br> line t?
Sveta_85 [38]

Answer:

  -1/5

Step-by-step explanation:

Perpendicular lines have slopes that are the opposite reciprocal of one another.

The slope of line t is the opposite reciprocal of the slope of line s:

  slope of t = -1/(slope of s)

  slope of t = -1/5

6 0
3 years ago
Fundamental theorem of calculus<br> <img src="https://tex.z-dn.net/?f=g%28s%29%3D%5Cint%5Climits%5Es_6%20%7B%28t-t%5E4%29%5E6%7D
mr_godi [17]

Answer:

\displaystyle g'(s) = (s-s^4)^6

Step-by-step explanation:

The Fundamental Theorem of Calculus states that:
\displaystyle \frac{d}{dx}\left[ \int_a^x f(t)\, dt  \right] = f(x)

Where <em>a</em> is some constant.

We can let:
\displaystyle g(t) = (t-t^4)^6

By substitution:

\displaystyle g(s) = \int_6^s g(t)\, dt

Taking the derivative of both sides results in:
\displaystyle g'(s) = \frac{d}{ds}\left[ \int_6^s g(t)\, dt\right]

Hence, by the Fundamental Theorem:

\displaystyle \begin{aligned} g'(s) & = g(s) \\ \\  & = (s-s^4)^6\end{aligned}

3 0
2 years ago
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