Answer:
a)
is the speed of each proton
b) ![F_c=3.97\times 10^{-13}\ N](https://tex.z-dn.net/?f=F_c%3D3.97%5Ctimes%2010%5E%7B-13%7D%5C%20N)
Explanation:
Given:
radius of path of motion, ![r=0.2\ m](https://tex.z-dn.net/?f=r%3D0.2%5C%20m)
we know charge on protons, ![q=1.6\times 10^{-19}\ C](https://tex.z-dn.net/?f=q%3D1.6%5Ctimes%2010%5E%7B-19%7D%5C%20C)
magnetic field strength, ![B=0.36\ T](https://tex.z-dn.net/?f=B%3D0.36%5C%20T)
we've mass of proton, ![m=1.67\times 10^{-27}\ kg](https://tex.z-dn.net/?f=m%3D1.67%5Ctimes%2010%5E%7B-27%7D%5C%20kg)
a)
From the equivalence of magnetic force and the centripetal force on the proton:
![F_B=F_C](https://tex.z-dn.net/?f=F_B%3DF_C)
![q.v.B=\frac{m.v^2}{r}](https://tex.z-dn.net/?f=q.v.B%3D%5Cfrac%7Bm.v%5E2%7D%7Br%7D)
![q.B=\frac{m.v}{r}](https://tex.z-dn.net/?f=q.B%3D%5Cfrac%7Bm.v%7D%7Br%7D)
where:
v = speed of the proton
![(1.6\times 10^{-19})\times 0.36=\frac{1.67\times 10^{-27}\times v}{0.2}](https://tex.z-dn.net/?f=%281.6%5Ctimes%2010%5E%7B-19%7D%29%5Ctimes%200.36%3D%5Cfrac%7B1.67%5Ctimes%2010%5E%7B-27%7D%5Ctimes%20v%7D%7B0.2%7D)
is the speed of each proton
b)
Now the centripetal force on each proton:
![F_c=m.\frac{v^2}{r}](https://tex.z-dn.net/?f=F_c%3Dm.%5Cfrac%7Bv%5E2%7D%7Br%7D)
![F_c=1.67\times 10^{-27}\times \frac{(6.898\times 10^6)^2}{0.2}](https://tex.z-dn.net/?f=F_c%3D1.67%5Ctimes%2010%5E%7B-27%7D%5Ctimes%20%5Cfrac%7B%286.898%5Ctimes%2010%5E6%29%5E2%7D%7B0.2%7D)
![F_c=3.97\times 10^{-13}\ N](https://tex.z-dn.net/?f=F_c%3D3.97%5Ctimes%2010%5E%7B-13%7D%5C%20N)
You have to draw a mathematical spatial axes .in order to judge is it right or not .. well you have to draw the crest and trough both of 1 cm in length and the total wavelength (same phase on the wave of 2 cm ) something like this
Answer:
The SI unit of thermal conductivity is watts per meter-kelvin (W/(m⋅K)).
Explanation:
hope this will help u
143m/s if you just perhaps by what you know you'll figure it out
Answer:
Please see below as the answer is self-explanatory.
Explanation:
The low band of the VHF TV Spectrum, spans channels 2-6, from 54 to 88 Mhz.
In the analog TV, in the Americas, the total bandwidth of any channel is 6 Mhz, with the visual carrier modulated in VSS (Vestigial Side Band) at 1.25 Mhz from the lowest frequency of the channel.
The aural carrier is located at 4.5 Mhz from the visual carrier, and is FM modulated.
For Channel 6, which spans between 82 and 88 Mhz, the visual carrier is at 83.25 Mhz, so the aural carrier is at 87.75 Mhz, which falls within the FM Band, so it is possible to listen the audio part of this channel in a FM radio receiver, even at a lower volume, due to the FM radio has a greater deviation than TV aural carrier.