Answer:
Explanation:
The question is incomplete.
The equation of motion is given for a particle, where s is in meters and t is in seconds. Find the acceleration after 4.5 seconds.
s= sin2(pi)t
Acceleration = d²S/dt²
dS/dt = 2πcos2πt
d²S/dt² = -4π²sin2πt
A(t) = -4π²sin2πt
Next is to find acceleration after 4.5 seconds
A(4.5) = -4π²sin2π(4.5)
A(4.5) = -4π²sin9π
A(4.5) = -4π²sin1620
A(4.5) = -4π²(0)
A(4.5) = 0m/s²
The AREA of the shaded region is the moving object's displacement.
The answer is C! I knew this way before taking the test
To solve this problem we will apply the concepts related to the Doppler effect. According to this concept, it is understood as the increase or decrease of the frequency of a sound wave when the source that produces it and the person who captures it move away from each other or approach each other. Mathematically this can be described as
Here,
= Original frequency
= Velocity of the observer
= Velocity of the speed
Our values are,
Using the previous equation,
Rearrange to find the velocity of the observer
Replacing we have that
Therefore the velocity of the observer is 16.2m/s
Thank you for posting your question here and Brainly!~
Even though you have not provided answer choices, I believe the answer is whatever letter corresponds with the answer: "It is rubbed with another object, and electrons move onto the rod."
Hope I helped!~ Brainliest appreciated.
