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IRISSAK [1]
3 years ago
9

How many grams are there in 7.5 X10^23 molecules of H2SO4?

Chemistry
2 answers:
mash [69]3 years ago
6 0
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

 </span><span>7.5 X10^23 molecules of H2SO4 ( 1 mol / 6.022x10^23 molecules ) (98.08 g / 1 mol ) = 122.15 grams H2SO4</span>
mel-nik [20]3 years ago
4 0

Answer : The mass of H_2SO_4 are, 117.6 grams.

Explanation :

First we have to calculate the moles of H_2SO_4.

As, 6.022\times 10^{23} molecules of H_2SO_4 present in 1 mole of H_2SO_4

So, 7.5\times 10^{23} molecules of H_2SO_4 present in \frac{7.5\times 10^{23}}{6.022\times 10^{23}}=1.2 mole of H_2SO_4

Now we have to calculate the mass of H_2SO_4.

\text{Mass of }H_2SO_4=\text{Moles of }H_2SO_4\times \text{Molar mass of }H_2SO_4

Molar mass of H_2SO_4 = 98 g/mole

\text{Mass of }H_2SO_4=1.2mole\times 98g/mole=117.6g

Therefore, the mass of H_2SO_4 are 117.6 grams.

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