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IRISSAK [1]
3 years ago
9

How many grams are there in 7.5 X10^23 molecules of H2SO4?

Chemistry
2 answers:
mash [69]3 years ago
6 0
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

 </span><span>7.5 X10^23 molecules of H2SO4 ( 1 mol / 6.022x10^23 molecules ) (98.08 g / 1 mol ) = 122.15 grams H2SO4</span>
mel-nik [20]3 years ago
4 0

Answer : The mass of H_2SO_4 are, 117.6 grams.

Explanation :

First we have to calculate the moles of H_2SO_4.

As, 6.022\times 10^{23} molecules of H_2SO_4 present in 1 mole of H_2SO_4

So, 7.5\times 10^{23} molecules of H_2SO_4 present in \frac{7.5\times 10^{23}}{6.022\times 10^{23}}=1.2 mole of H_2SO_4

Now we have to calculate the mass of H_2SO_4.

\text{Mass of }H_2SO_4=\text{Moles of }H_2SO_4\times \text{Molar mass of }H_2SO_4

Molar mass of H_2SO_4 = 98 g/mole

\text{Mass of }H_2SO_4=1.2mole\times 98g/mole=117.6g

Therefore, the mass of H_2SO_4 are 117.6 grams.

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A 32 L samples of xenon gas at 10°C is expanded to 35 L. Calculate the final temperature.
morpeh [17]

Answer:

              Final Temperature = 36.54 ⁰C

Explanation:

Lets suppose the gas is acting ideally, then according to Charle's Law, "<em>The volume of a fixed mass of gas at constant pressure is directly proportional to the absolute temperature</em>". Mathematically for initial and final states the relation is as follow,

                                                V₁ / T₁  =  V₂ / T₂

Data Given;

                  V₁  =  32 L

                  T₁  =  10 °C = 283.15 K             ∴ K = °C + 273.15

                  V₂  =  35 L

                  T₂  =  ??

Solving equation for T₂,

                         T₂  =  V₂ × T₁  / V₁

Putting values,

                         T₂  =  (35 L × 283.15 K) ÷ 32 L

                         T₂  =  309.69 K     ∴ ( 36.54 °C )

Result:

           As the volume is increased from 32 L to 35 L, therefore, the temperature must have increased from 10 °C to 36.54 °C.

3 0
4 years ago
Is aluminum foil a compound element or mixture?
timurjin [86]
Aluminum is an element.  If there's nothing else in the foil
besides aluminum, then the foil is entirely an element.
5 0
3 years ago
An example of basic research is A) the development of new plastics that can be recycled. B) the study of the relationship betwee
elena-s [515]

Answer:

C) the study of the composition of the atom.

Explanation:

A research can be defined as a systematic investigation or careful consideration of study with respect to a particular problem using scientific methods such as collection of data, documenting critical information, analysis of data, and the establishment of facts in order to reach new conclusions.

Similarly, a basic research is an approach to research that's typically theoritical and it's aimed at developing a theory, searching for the truth or gain a better understanding about a phenomenon, subject, or basic laws on nature.

In this context, an example of basic research is the study of the composition of the atom.

An atom can be defined as the smallest unit comprising of matter that forms all chemical elements. Thus, atoms are basically the building blocks of matters and as such determines or defines the structure of a chemical element.

Generally, atoms are typically made up of three distinct particles and these are protons, neutrons and electrons.

5 0
2 years ago
A chemist determined by measurements that 0.050 moles of aluminum participated in a chemical reaction. Calculate the mass of alu
Law Incorporation [45]

Answer:

13.5 g

Explanation:

This question is solved easily if we remember that the number of moles is obtained by dividing the mass into the atomic weight or molar mass depending if we are referring to elements or molecules.

Therefore, the mass of aluminum in the reaction will the 0.050 mol Al times the atomic weight of aluminum.

number of moles = n = mass of Al / Atomic Weight Al

⇒ mass Al = n x Atomic Weight Al = 0.050 mol x 27 g mol⁻¹

                                                         = 13.5 g

We have three significant figures in 0.050 and therefore we should have three significant figures in our answer.

           

8 0
3 years ago
During glycolysis, for every 6 moles of glucose that enter the pathway, how many moles of atp are used? how many moles atp are g
Goryan [66]
During the process of glycolysis 1 mole of glucose yields 2 pyruvic acid. In the process 2 ATPs molecules are used up and 4 other ATP molecules are produced by substrate level phosphorylation and 2 NADH are also produced. Therefore; for six moles of glucose; 12 ATP molecules will be used up, 24 ATP molecules will be generated, 12 moles of NADH will be used and 12 moles of pyruvate are made. 
7 0
3 years ago
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