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Paha777 [63]
2 years ago
10

This is urgent, please answer! What is the area of this composite figure?

Mathematics
2 answers:
Reika [66]2 years ago
4 0
Answer: 978 in^2

Explanation:
30 x 24 = 720
12 x 9 = 108
(15 x 20)/2 = 150
150 + 108 + 720 = 978
Advocard [28]2 years ago
4 0

Answer: 978 in. squared

Step-by-step explanation:

area of the rectangle : 24 x 30 = 720

area of the two triangles combined : (9 x 12) ÷ 2 = 54 x 2 = 108

area of the triangle on top of the other triangle : (20 x 15) ÷ 2 = 150

720 + 108 +150 = 978

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Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans
zloy xaker [14]
Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

The perimeter of the square is given by 4(x + 4) = 4x + 16

The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12

For the perimeters to be the same

4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2

The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.



Part B:

The area of the square is given by

Area=(x+4)^2=x^2+8x+16

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

x^2+8x+16=6x+8 \\  \\ \Rightarrow x^2+8x-6x+16-8=0 \\  \\ \Rightarrow x^2+2x+8=0 \\  \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2}  \\  \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2}  \\  \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
7 0
3 years ago
EM Company produces two types of laptop computer bags. The regular version requires $32 in capital and 4 hours of labor and sell
expeople1 [14]

Answer:

Step-by-step explanation:

Given that EM company produces two types of laptop computer bags.

Let regular version produced be R and deluxe version be D

Total capital required

= 32R+38D\leq 2100

Total labor hours required

=4R+6D\leq 280

Sales revenue = 46R+55D

Solving the two constraints we have

10D \leq 140

D can be atmost 14 and hence R can be 49

Otherwise if D is made 0, R = 65 maximum

If R is made 0, D maximum is 46

Thus corner points are (65,0) (0.,46) or (49,14)

Sales revenue for (65,0) = 2990

(0,46) is 2530

(49,14) is 3024

Maximum when R =14 and D is 49

5 0
3 years ago
Solve both by elimination can someone help?<br> 2x-5y=-9 , 4x+5y=12<br><br> 3x-2y=12 , 7x-5y=17
lyudmila [28]

Answer:

x=1/2, y=2;    

Step-by-step explanation:

First pair:

2x-5y =-9

4x+5y=12

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x = 1/2

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1-5y = -9

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8 0
2 years ago
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DiKsa [7]

Answer:

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2 years ago
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julsineya [31]
You can get a 5 this many ways.
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That number is 4
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4/36 = 1/9 <<<< Answer.
B <<<< answer
4 0
2 years ago
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