14. Calculate the mass in grams of oxygen required to react completly with 0.75 moles of Aluminum.

Chemistry

1 answer:

cluponka [151]2 years ago

8 0

3mols of O_2 react with 4mol of Al
3/4=0.75mol O_2 react with 1mol of Al

Moles of O_2:-

0.75(0.75)
0.5625mol

Mass of O_2:-

moles(Molar mass)
0.5625(32)
18g

Option B

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$4Al _{(s)} + 3 O_{2} _{(g)}$ → $2 Al_{2} O_{3}$

Now if mass of aluminum = 145 g
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