Types of Bonds can be predicted by calculating the
difference in electronegativity.
If, Electronegativity difference is,
Less
than 0.4 then it is Non Polar Covalent
Between 0.4 and 1.7 then it is Polar Covalent
Greater than 1.7 then it is Ionic
For CaCl₂,
E.N of Chlorine = 3.16
E.N of Calcium = 1.00
________
E.N Difference 2.16 (Ionic Bond)
For C-H Bond in C₆H₁₂O₆,
E.N of Carbon = 2.55
E.N of Hydrogen = 2.20
________
E.N Difference 0.35 (Non-Polar Covalent Bond)
For C-O Bond in C₆H₁₂O₆,
E.N of Oxygen = 3.44
E.N of Hydrogen = 2.55
________
E.N Difference 0.89 (Polar Covalent Bond)
For O-H Bond in C₆H₁₂O₆,
E.N of Oxygen = 3.44
E.N of Hydrogen = 2.20
________
E.N Difference 1.24 (Polar Covalent Bond)
For MgO,
E.N of Oxygen = 3.44
E.N of Magnesium = 1.31
________
E.N Difference 2.13 (Ionic Bond)
For Na₂O,
E.N of Oxygen = 3.44
E.N of Sodium = 0.93
________
E.N Difference 2.51 (Ionic Bond)
For SiO₂,
E.N of Oxygen = 3.44
E.N of Silicon = 1.90
________
E.N Difference 1.54 (Polar Covalent Bond)
Result:
Compounds having Ionic Bonds are Na₂O, MgO and CaCl₂.
Answer:
The correct answer is a glucose.
Explanation:
Proximal convulated tubule is an important part of the nephron of kidney.proximal convoluted tubule helps in the the reabsorption of Na+ from the glomerular filtrate along the transport of glucose from the later.This type of transport is called co transport process.
The co transport process is mediated by Na+ glucose symporter protein which uses the secondary active transport mechanism to facilitate the re absorption of Na+ along with glucose.
Answer:
6.517.
Explanation:
- It is known that for pure water: [H₃O⁺] = [OH⁻], so water is neutral.
<em>Kw = [H₃O⁺][OH⁻] = 9.25 x 10⁻¹⁴.</em>
∵ [H₃O⁺] = [OH⁻].
∴ [H₃O⁺]² = 9.25 x 10⁻¹⁴.
∴ [H₃O⁺] = √(9.25 x 10⁻¹⁴) = 3.041 x 10⁻⁷ M.
∵ pH = - log[H₃O⁺]
<em>∴ pH</em> = - log(3.041 x 10⁻⁷) = <em>6.517.</em>
Answer : The number of moles of is 0.6156 moles.
Solution : Given,
Mass of = 186.7 g
Molar mass of = 303.256 g/mole
Formula used :
Now we have to calculate the moles of .
Therefore, the number of moles of is 0.6156 moles.