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navik [9.2K]
3 years ago
12

A _____ is a device that multiplies force or increases speed and makes work easier.

Physics
2 answers:
Lena [83]3 years ago
5 0
Machine................
max2010maxim [7]3 years ago
4 0
Machine is the answer :)
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If caught outside in a thunderstorm, find a low spot away from trees, fences, and poles. If your skin tingles and hair stands on end, lightning is about to strike. Crouch down immediately, balancing on the balls of your feet, placing hands on knees with head between them.

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The bleeder is opened at a caliper and no brake fluid flows out. Technician A says that this is normal and that brake fluid shou
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For the fact no break fluid flows out Of the bleeder valve when It’s opened, that means there’s a blockage stopping the fluid from flowing off.

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3 years ago
Three cars (car F, car G, and car H) are moving with the same speed and slam on their brakes. The most massive car is car F, and
Crazy boy [7]

To solve this problem it is necessary to apply the concepts related to Normal Force, frictional force, kinematic equations of motion and Newton's second law.

From the kinematic equations of motion we know that the relationship of acceleration, velocity and distance is given by

v_f^2=v_i^2+2ax

Where,

v_f = Final velocity

v_i = Initial Velocity

a = Acceleration

x = Displacement

Acceleration can be expressed in terms of the drag coefficient by means of

F_f = \mu_k (mg)  \rightarrowFrictional Force

F = ma \rightarrow Force by Newton's second Law

Where,

m = mass

a= acceleration

\mu_k = Kinetic frictional coefficient

g = Gravity

Equating both equation we have that

F_f = F

\mu_k mg=ma

a = \mu_k g

Therefore,

v_f^2=v_i^2+2ax

0=v_i^2+2(\mu_k g)x

Re-arrange to find x,

x = \frac{v_i^2}{2(-\mu_k g)}

The distance traveled by the car depends on the coefficient of kinetic friction, acceleration due to gravity and initial velocity, therefore the three cars will stop at the same distance.

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3 years ago
Sjskskszpd no djdkzsnkakzx d
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3 years ago
Un pintor de 75.0 kg sube por una escalera de 2.75 m que está inclinada contra una pared vertical. La escalera forma un ángulo d
dezoksy [38]

Answer:

Work done, W = 1786.17J

Explanation:

The question says "A 75.0-kg painter climbs a 2.75-m ladder that is leaning against a vertical wall. The ladder makes an angle of 30.0 ° with the wall. How much work (in Joules) does gravity do on the painter? "

Mass of a painter, m = 75 kg

He climbs 2.75-m ladder that is leaning against a vertical wall.

The ladder makes an angle of 30 degrees with the wall.

We need to find the work done by the gravity on the painter.

The angle between the weight of the painter and the displacement is :

θ = 180 - 30

= 150°

The work done by the gravity is given by :

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Hence, the required work done is 1786.17 J.

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2 years ago
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