Answer:A 2.2kg block of ice slides across a rough floor. Its initial velocity is 2.5m/s and its final velocity is 0.50m/s. How much of the ice block melted as a result of the work done by friction? (Latent Heat of water is 3.3*10^5J/kg)
Explanation:
A machine that is interesting will be the homework machine. The way it works is you put your homework inside a slot, and you have to write any three letter word so the machine knows what handwriting to use. In 2 minutes your homework will be complete in your writing.
The strength of the force of friction depends on two factors; the type of surfaces involves and the force that the surfaces are being push together
Answer:
7 meters, 2.8 meters
Explanation:
work done (nm) = force (n) * distance (m)
140= 20 * m
140/20 = m
m=7 meters
140= 50 * m
140/50 = m
m= 2.8 meters
4.6 j more. To get this take 7 and multiply it by 3.5 to get 24.5 take the x which is what you’re looking for and multiply it by the 2.1 to get 2.1x. Take 24.5 and divide it by 2.1 x and get 11.6. Subtract 11.6 by 7 and get 4.6
