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stiv31 [10]
3 years ago
11

1. What are 3 main categories of waste and what is the largest contribution of municipal solid waste?​

Physics
1 answer:
Tasya [4]3 years ago
5 0
Organic materials continue to be the largest component of MSW. Paper and paperboard account for 27 percent and yard trimmings and food account for another 28 percent. Plastics comprise about 13 percent; metals make up 9 percent; and rubber, leather, and textiles account for 9 percent.
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How do burrowing rodents affect soil fertility? A) They feed on the nutrients in the soil leaving little for plants to absorb. B
jek_recluse [69]

How do burrowing rodents affect soil fertility? A) They feed on the nutrients in the soil leaving little for plants to absorb. B) They loosen the soil and make it difficult for plant roots to take a firm grip. C) They decompose the remains of plants and animals and add nutrients to the soil. D) They provide means by which air can enter the soil and reach the roots of plants.

the answer is a

7 0
3 years ago
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What is released when rocks shift or move along a tectonic plate boundary?
Phoenix [80]

Answer:

juuhu

Explanation:

jjj

6 0
3 years ago
A proton, mass 1.67 × 10−27 kg and charge +1.6 × 10−19 c, moves in a circular orbit perpendicular to a uniform magnetic field of
stellarik [79]

Time taken by proton to complete one complete circular orbit= 7.28 x 10⁻⁸ s

Explanation:

For proton, the centripetal force required for circular motion is provided by the magnetic force,

so Fm= Fc

q v B = m v²/r

m= mass of charged particle

v= velocity

B =magnetic field

q= charge

r= radius of circular path

v= q B r/m

now v= r ω

ω= angular velocity

ω r = q B r /m

ω=q B /m

now ω= 2π/T where T =time period

so 2π/T=q B/m

T= 2 πm/q B

T= 2π (1.67 x 10⁻²⁷)/ [( 1.6 x 10⁻¹⁹)* (0.9)]

T= 7.28 x 10⁻⁸ s

6 0
3 years ago
Which statement is true?
vladimir2022 [97]
<span>a.current varies throughout a parallel circuit. 

Hope this helps!</span>
8 0
3 years ago
A bicycle rim has a diameter of 0.65 m and a moment of inertia, measured about its center, of 0.21 kg⋅m2What is the mass of the
stepan [7]

Answer:

m = 1.99 kg = 2 kg

Explanation:

The moment of inertia of a bicycle rim about it's center is given by the following formula:

I = mr^{2}\\

where,

I = Moment of Inertia of the Bicycle Rim = 0.21 kg.m²

r = Radius of the Bicycle Rim = Diameter of the Bicycle Rim/2

r = 0.65 m/2 = 0.325 m

m = Mass of the Bicycle Rim = ?

Therefore,

0.21\ kg.m^{2} = m(0.325\ m)^{2}\\m = \frac{0.21\ kg.m^{2}}{(0.325\ m)^{2}}\\

<u>m = 1.99 kg = 2 kg</u>

3 0
3 years ago
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