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QveST [7]
3 years ago
11

A motorcycle stunt driver zooms off the end of a cliff at a speed of 30 meters per second. If he lands after 0.75 seconds, what

is the height of the cliff?
Physics
1 answer:
marissa [1.9K]3 years ago
5 0
u = 30ms^{-1}
\\t = 0.75s
\\a = 9.8ms^{-2} (Gravity)
\\s = ?

s = ut +  \frac{1}{2}at^2
\\s = (30)(0.75)+ \frac{1}{2}(9.8)(0.75)^2
\\s = 22.5 + 2.75625
\\s = 25.25625

<u>s = 25.3 m (3 sf)</u>

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