Question

A motorcycle stunt driver zooms off the end of a cliff at a speed of 30 meters per second. If he lands after 0.75 seconds, what is the height of the cliff?

Answer 1

$u = 30ms^{-1} \\t = 0.75s \\a = 9.8ms^{-2} (Gravity) \\s = ?$

$s = ut + \frac{1}{2}at^2 \\s = (30)(0.75)+ \frac{1}{2}(9.8)(0.75)^2 \\s = 22.5 + 2.75625 \\s = 25.25625$

s = 25.3 m (3 sf)